a. Calculate the total molar amount and mole fractions of methanol, air (N2+O2) and water fed to the reactor. b. Determine the extents of reaction, ??̇1and ??̇2. c. Calculate the fractional conversion of methanol.

1. A house needs 200,000 Btu per day so that its temperature remanins at 68oF. How much CaCl26H2O(s) needs to be used to save enough energy for one day use? The process contains the heating of CaCl26H2O(s) from 68oF to 86oF and the reaction CaCl26H2O(s) = CaCl22H2O(s) + 4H2O(g). The water from the dehydration evaporates during the process. CaCl26H2O(s): ΔHof=-2607.89kJ/gmol, Cp=1.34J/g(oC) CaCl22H2O(s): ΔHof=-1402.90kJ/gmol, Cp=0.97J/g(oC)

REACTION ENGINEERING  Consider a heterogeneous gas-phase catalytic reaction:AB(g)→A(g)+B(g) (Catalyst) The surface reaction mechanism follows three steps: AB(g) +S <----> AB*S (Adsorption)AB*S<----> B*S+A(g) (Surface reaction)B*S <---> B(g) + S (Desorption) a) Derive the initial rates (AR) of the reaction, assuming there is no product (ie., A and B) in the feed (ie., PA Pao=0), assuming adsorption is the rate determining step. Use initial pressure of AB (ie., PARA), total number of sites on the surface (C), and the rate and equilibrium constants in the expressions.Hint: Based on the reaction mechanism, only AB and B are adsorbed on the surface, i.e., there is no evidence that A alone can be adsorbed on the surface.

Prepare a material flowsheet similar to Figure 6.1 (shown below) for production of 2400 lb-mol/hr of Vinyl Chloride (VC) based on the reaction path #5 with the operating parameters provided below. You MUST show the Molar flow rates of ALL compounds in ALL streams in your flowsheet. Reaction Path #5. Balanced process for Chlorination of Ethylene C2H4 + Cl2--> C2H4CI2 (C) Ileat Liberated Ileat Absorbed y Reactinn 150 x 10 Blutr duriag Reaction = 52 x 10 Bluhr C2H4 + 2HCI + 1/2 O2--> C2H4CI2 + H2O 2C2H4CI2 --> 2C;H3CI + 2HCI (E) (D) 58.300 Ibhr 2C2H4 + Cl2 +1/2 O2 --> 2C2H3CI + H2O (C) 100% Conv. of Cl2 at 80°C and 150 kPa with 15% (G) Direct Chlorination YƯ C, 15 atm Pyrolysis Sorc +CH,CI- 26 ata HCI CH.CI, CAL 11.3,4KI hr 158,I Ihyhr CH,CI, C1,CI 4,900 Ihhr CH, -a CH,CI, excess C2H4 CH,ClCH,CI + HCI (E) 100% Conv. of HCl at 275°C and 150 kPa with 5% 105,500 Ib'hr excess C2Н4 (D) 75% Conv. At 500 °C and 3000 kPa. Water is separated from the mixture before entering Figure 6.1 reactor D.

(a) Consider the mass transfer-limited reaction: A → 2B DAB = 0.01 cm²s-1 What would your concentration (mole fraction) profile look like as a function of distance (i.e. z/8)? What is the flux of A?

Start with the general mass balance relationship  In – Out + Rxn = Accum  and derive a formula that allows you to calculate the value of the first order reaction rate constant, k, given the half-life of a compound.  Use the equation to determine the value of k for carbon tetrachloride (CCl4) given that CCl4 has a half-life of 8,030 days in air.

Calculate the solubility of Zn(OH)2 in a 0.0300M K2SO4 solution using activities and concentration. Determine the % error when using only concentrations (assuming that the actual solubility is the determined with the activity). The Kps of Zn(OH)2 is 1.2 x 10-17

please quickly thanks !!!!

REACTION ENGINEERING    Consider a heterogeneous gas-phase catalytic reaction:AB(g)→A(g)+B(g) (Catalyst) The surface reaction mechanism follows three steps: AB(g) +S <----> AB*S (Adsorption)AB*S<----> B*S+A(g) (Surface reaction)B*S <---> B(g) + S (Desorption) (a) Derive the rate law assuming desorption is rate-limiting. Express the overall reaction rate (- rab) in terms of total number of sites on the surface, C. partial pressures of the gas species (ie., Pab, Pa and Pb), rate constants of adsorption, the surface reaction, and desorption (ka,ks, and kd), and the equilibrium constants of adsorption, the surface reaction, and desorption (ie., K. Ks and Kd). Hint: Based on the reaction mechanism, only AB and B are adsorbed on the surface, i.e., there is no evidence that A alone can be adsorbed on the surface.

2. Find the AH for the reaction below, given the following reactions and subsequent AH values: 2C2(g) + H2O(g) – C2H2(g) + /2 02(g) C2H2(g) + 2H2(g) C2He(g) AH = -94.5 kJ H20(g) - H2(g) + % O2 (g) AH =71.2 kJ C2H6(g) + /2 Oz(g) - 2 CO2(9) + 3 H2O(g) AH = -283 Kj