A. By calculations show that: Ve v =(2 sin(@ct) + d x cos[(wc – Wm)t] – d x cos[(wc + wm)t]) where d = (sometimes called the depth of modulation if given as a percentage). B. Using MATLAB, plot on separate figures the following, assuming wm = 1, wc = 10 rad/s, Ve = Vm = 1 volt., time taken from 0 to 10 seconds. Vc
A. By calculations show that: Ve v =(2 sin(@ct) + d x cos[(wc – Wm)t] – d x cos[(wc + wm)t]) where d = (sometimes called the depth of modulation if given as a percentage). B. Using MATLAB, plot on separate figures the following, assuming wm = 1, wc = 10 rad/s, Ve = Vm = 1 volt., time taken from 0 to 10 seconds. Vc
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![A. By calculations show that:
Ve
v =(2 sin(@ct) + d x cos[(wc – Wm)t] – d x cos[(wc + wm)t])
where d = m (sometimes called the depth of modulation if given as a percentage).
B. Using MATLAB, plot on separate figures the following, assuming wm = 1, Wc = 10 rad/s, Ve
Vm = 1 volt., time taken from 0 to 10 seconds.
Vc](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb144836-1ae2-477c-86fd-3b713b7796cc%2F0a657acb-dbde-4a3e-b294-bbdd8c7ef2fa%2Fxi1ml4c.png&w=3840&q=75)
Transcribed Image Text:A. By calculations show that:
Ve
v =(2 sin(@ct) + d x cos[(wc – Wm)t] – d x cos[(wc + wm)t])
where d = m (sometimes called the depth of modulation if given as a percentage).
B. Using MATLAB, plot on separate figures the following, assuming wm = 1, Wc = 10 rad/s, Ve
Vm = 1 volt., time taken from 0 to 10 seconds.
Vc
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