A. Answer as directed. 5 pts each. 1. Draw a molecule that contains sp, sp², and sp³ hybridized carbon atom. 2. Explain why 1,2-dichloroethyne is nonpolar while cis-1,2-dichloroethene is not. Provide illustrations to support your answer. B. Given the molecular formulae, provide the table with relevant details. Methylamine is already done for you.. Condensed Formula CH3NH2 (methylamine/ methanamine) Drawing and Hybridization Molecular Geometry Approximate Bond Angle(s) with Drawing Molecular Polarity H-N-H: <109.5° H-N-C: >109.5° CH3 sp³ (around N) H CF4 '\' (around C) The angle formu (around Carbon-3) 10SY Polar " CH3 H Condensed Formula Drawing and Molecular Geometry Hybridization Approximate Bond Angle(s) with Drawing (around the rightmost Carbon) 4 CH,CH₂SH (around S) 5 CHOOCH (dimethyl peroxide) (around left side O) 6 CH₁C=N (around middle C) 7 CH,COOH 8 CH3COOH (around Carbon-1) (around Carbon-2) Molecular Polarity

I'm confused on how to do B. Help please!

D.4.

Meet benzylpenicillin, a common antibiotic for bacterial infections. Answer the following parts about this compound. a. Label all the functional groups present. b.For every heteroatom (i.e.atoms that are not CorH),predict the expected hybridization. c.Circle every carbon with a hydrogen capable of participating in hyperconjugation with a double bond. d.Draw one key resonance structure for each functional group capable of resonance, and one resonance hybrid with partial charges as applicable. e. Give the IUPAC name for this compound. Just kidding! It’s 3,3-dimethyl-7- oxo-6-(phenylacetamido)-4-thia-1-azabicyclo[3.2.0]heptane-2-carboxylic acid. Now, sit back and appreciate the limitations of naming—it’s only useful insofar as we understand each other.