A = x²yzî- 2xz3j+ xz² k B = 2xî+ yj- x² k a2 - (A × B) дхду FİND THİS (1,0, –2) ON POİNT

Using the result from part (a), evaluate = (^²+x²) y(x). (choose one) ( 1 + x²) √(x) y (x) X ( 121 - 12/27) 1 (X) y(x) ○ (1-x²) y(x) ○ (1+x²) y(x) 2 (1+77) w(0) y(x) (1-27) (0) y(x) 1 2 + X 2 2 y(x)

Problem 1 Use the properties of Gamma functions to solve these expressions by hand. a program such as a T[ ] × [4] b C 3 — 92 xr 5 9 T[-2] × [2] Г xr 4 4

A valid, but probably useless, dimensionless group is givenby (μT0g)/ (YLα) , where everything has its usual meaning,except α . What are the dimensions of α ?( a ) θL-1T-1 , ( b ) θL-1T-2 , ( c ) θML-1 , ( d ) θ-1LT-1 ,( e ) θLT-1

If A =〖yz〗^2 i-3xz^2j +2xyz k, B = 3xi +4zj -xyk and ∅= xyz, findd^2/dxdy [Ax (B.∅)] at P(1, 1, 1)

Function f is defined by 5 = 21 @where a = 4.35 # 0.04 and y = 1.25 # 0.03 Calculate the absolute uncertainty in f. Specify your answer up to 3 decimal places.

If v→1=34i^+17j^, v→2x=80, and v→1 X v→2= 28k^ then :  v2y =  v2z=