(a) Write a complete PL/SQL Cursor to retrieve the following information. Fetch row number, Employee Id, First Name of the employees - Select all the employees with Employee_no < 115 Use the complete cycle of declaring, opening, fetching, and closing a cursor, including use of cursor attributes. - Format the output as shown below Script Output x # Task completed in 0.299 seconds Lauren Lisa Just FETCHED row 1- Employee ID: 110 - First Name: Just FETCHED row 2- Employee ID: 111- First Name: Just FETCHED row 3- Employee ID: 112 - First Name: Just FETCHED row 4- Employee ID: 113 First Name: Just FETCHED row 5- Employee ID: 114 - First Name: Marg Dave Steve (b) Modify your program to use the CURSOR FOR LOOP to achieve the same output

Handwork problem (also includes MATLAB applications): HW10_1 First, compute the integral analytically. Then estimate the integral to 6 decimal places, as instructed. a) handwork Use multiple applications of the trapezoid rule, with n=6. .3 dx b) handwork Apply the composite trapezoid rule, with n=6. (3x + 1)3 c) MATLAB Apply the composite trapezoid rule, with n=6, 12 & 24 d) handwork Use multiple applications of Simpson's 1/3 rule, with n=6. e) handwork Apply the composite Simpson's 1/3 rule, with n=6. f) MATLAB Apply the composite Simpson's 1/3 rule, with n= 6, 12 & 24 for all cases, handwork & MATLAB: Compare all results with the exact integral, and compute the relative errors using MATLAB and publish as pdf.

using chapters 1 to 7 from the book c how to program 8 edition

Identify the default segment register assigned for item in the left column. A. DI • v SP v BX B. ES vDI C. CS v BP D. SS v SI E. IP F. DS G. SI

Systems Programming Purpose: The purpose of this assignment is to practice loop instructions and array iterations in M6800 assembly language programming. Write an assembly language program which implements the following C code that is a find minimum problem solution implementation: int A[10] = {8, 14, 6, 16, 5, 5, 10, 9, 4, 11}; int i = 0; int min = 255; // This is the largest number 8-bit accumulators can hold. while (i < 10) { if (A[i] < min) min = A[i]; } Your solution should be able to handle all possible array elements and orderings for any value an accumulator can hold. You should treat variable į as XR in assembler (index register) and store variable min in the address 60H. 0010: 00 00 00 00 00 00 00 00 0O 00 00 00 00 00 00 00 8628: 00 060 00 00 00 600 00 00 00 08 08 00 6 00 00 00 0030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 0040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 0050: 00 G0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 006 0: 00 00 00 00 00 00 00 00 00 08 00…

Explain the differences between z-value and D-value.