Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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- After graduation, you take a job with the Acme energy services company. Your first job is to purchase high efficiency heat pumps. The heat pumps employ mechanical power and a heat engine to provide heat at TH = 100°C. A low temperature heat sink at TC = 20ºC is also available. A salesman shows you two models. Performance data for each model operating at steady state are provided in the Figure belowarrow_forwardThis Concepts revolves around thermodynamics and this practice example may need a PV diagram Directions are belowarrow_forwardAir within a piston-cylinder assembly executes a Carnot heat pump cycle, as shown in the figure below. For the cycle, TH = 500 K and Tc = 300 K. The energy rejected by heat transfer at 500 K has a magnitude of 1000 kJ per kg of air. The pressure at the start of the isothermal expansion is 325 kPa. Tc. p-v diagram for a Carnot gas refrigeration or heat pump cycle. Assuming the ideal gas model for the air, determine: (a) the magnitude of the net work input, in kJ per kg of air, and (b) the pressure at the end of the isothermal expansion, in kPa.arrow_forward
- A refrigerator operates according to a Brayton cycle, diagrammed below. The gas conditions (gamma=1.4) at point 1 are P1,V1 and T1=100K. It is known that V1 =10V2=5V3=V4/2.Consider that Tf is the temperature of the cold source and Tq is the temperature of the hot source. It is known that Tq and Tf are, respectively, the maximum and minimum possible for the refrigerator to operate under these conditions. reservoirs would have a coefficient of performance closer to:arrow_forwardAir within a piston-cylinder assembly executes a Carnot heat pump cycle, as shown in the figure below. For the cycle, TH = 600 K and Tc = 300 K. The energy rejected by heat transfer at 600 K has a magnitude of 1000 kJ per kg of air. The pressure at the start of the isothermal expansion is 325 kPa. p-v diagram for a Carnot gas refrigeration or heat pump cycle. Assuming the ideal gas model for the air, determine: (a) the magnitude of the net work input, in kJ per kg of air, and (b) the pressure at the end of the isothermal expansion, in kPa.arrow_forwardPlease help me out. Thermodynamics. Thank you.arrow_forward
- Shown in the figure below is the cycle undergone by a Heat Pump. Your heat pump runs using 38.55 moles of monatomic Helium gas. At point a in the figure, the temperature is T₂ = 321 Kelvin and the pressure is Pa = 216000 Pascals. During the process a→b, the Volume of the system Quadruples. P Cv= Cp Y = C с a STATE a b isothermal P (Pa) b V Joules/(mole. K); Joules/(mole K); V (m³) T (K) PROCESS W (J) a-b b-c c-a Total Qhot = Qcold = Performance Coefficient = Joules; Joules; Q (J) AU (J) Activate Windows Go to Settings to activate Windowarrow_forwardIn an absorption refrigerator, the energy driving the process is sllPplied not as work, but as heat from a gas flame. (Such refrigerators commonly use propane as fuel, and are used in locations where electricity is unavailable. *) Let us define the following symbols, all taken to be positive by definition: Qf = heat input from flame Qe = heat extracted from inside refrigerator Qr = waste heat expelled to room Tf = temperature of flame Te temperature inside refrigerator Tr = room temperature Explain why the "coefficient of performance" (COP) for an absorption refrigerator should be defined as Qc/Qf.arrow_forwardIn an absorption refrigerator, the energy driving the process is sllPplied not as work, but as heat from a gas flame. (Such refrigerators commonly use propane as fuel, and are used in locations where electricity is unavailable. *) Let us define the following symbols, all taken to be positive by definition: Qf = heat input from flame Qe = heat extracted from inside refrigerator Qr = waste heat expelled to room Tf = temperature of flame Te temperature inside refrigerator Tr = room temperature Use the second law of thermodynamics to derive an upper limit on the COP, in terms of the temperatures Tf, Te, and Tr alone.arrow_forward
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