A woodpecker's brain is specially protected from large decelerations by tendon-like attachments inside the skull. While pecking on a tree, the woodpecker's head comes to a stop from an initial velocity of 0.600 m/s in a distance of only 2.00 mm. (a) Find the acceleration in m/s2 and in multiples of g ⎝g = 9.80 m/s2⎞ (b) Calculate the stopping time. (c) The tendons cradling the brain stretch, making its stopping distance 4.50 mm (greater than the head and, hence, less deceleration of the brain). What is the brain's deceleration, expressed in multiples of g ?

A woodpecker's brain is specially protected from large decelerations by tendon-like attachments inside the skull. While pecking on a tree, the woodpecker's head comes to a stop from an initial velocity of 0.600 m/s in a distance of only 2.00 mm. (a) Find the acceleration in m/s2 and in multiples of g ⎝g = 9.80 m/s2⎞ (b) Calculate the stopping time. (c) The tendons cradling the brain stretch, making its stopping distance 4.50 mm (greater than the head and, hence, less deceleration of the brain). What is the brain's deceleration, expressed in multiples of g ?

Name: A woodpecker's brain is specially protected from large decelerations b
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: A woodpecker's brain is specially protected from large decelerations by tendon-like attachments inside the skull. While pecking on a tree, the woodpecker's head comes to a stop from an initial velocity of 0.600 m/s in a distance of only 2.00 mm. (a)

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 10P: An object moves along the x axis according to the equation x = 3.00t2 2.00t + 3.00, where x is in...

See similar textbooks

Similar questions

A human-powered vehicle (HPV) team wants to model the acceleration during the 260-m sprint race (the first 60 m is called a flying start) using a = A – Cv, where a is acceleration in m/s2? and v is the velocity in m/s. From wind tunnel testing, they found that C = 0.0012 m-1. Knowing that the cyclist starts from rest and is going 110 km/h at the 260-meter mark, what is the value of A? POSE HULMAN
Q. 12 In S.H.M. path length is 4 cm and maximum acceleration is 2n cm/s?. Time period of motion is (b) V2s 2 S (a) 2 s (c) 4 s (d) 1/2s
A rocket sled having an initial speed of 150 mi/hr is slowed by a channel of water. Assume that during the braking process, the acceleration a is given by a(v)=-mu v², where v is the velocity and mu is a constant. If it requires a distance of 2000 ft to slow the sled to 15 mi/hr, determine the value of mu?
The position of a particle for t > 0 is given by r⃗ (t) = 43.02i + 7.0 t3j + 5.0 t-2k̂ m.( a)What is its speed at t = 1.0 s and t = 3.0 s? (b) What is the average velocity between t = 1.0 s and t = 2.0 s?
An object moves along the x axis according to the equation x = 3.85t? 2.00t + 3.00, where x is in meters and t is in seconds. (a) Determine the average speed between t = 2.10 s and t = 4.10 s. 13 The average speed is the distance traveled divided by the time. Is the distance traveled equal to the displacement in this case? m/s (b) Determine the instantaneous speed at t = 2.10 s. m/s Determine the instantaneous speed at t = 4.10 s. m/s (c) Determine the average acceleration between t = 2.10 s and t = 4.10 s. m/s² (d) Determine the instantaneous acceleration at t = 2.10 s. m/s² Determine the instantaneous acceleration at t = 4.10 s. m/s? (e) At what time is the object at rest? S
A car is traveling on a straight, level road under wintry conditions. Seeing a patch of ice ahead of her, the driver of the car slams on her brakes and skids on dry pavement for 70 m, decelerating at 6.0 m/s2. Then she hits the icy patch and skids again. The car takes a duration of 85.0 s to come to rest during the second skid. If her initial speed was 50 m/s, what was the magnitude of the deceleration on the ice during the second skid. 1. Which of the following kinematic equations would you use to determine the velocity of the car after skidding on the dry pavement for 70 m? 2. Determine the velocity of the car after skidding on the dry pavement for 70 m. 3. Which of the following kinematic equations would you use to determine the deceleration of the car after skidding to a stop on the icy patch? 4. Determine the magnitude of the deceleration of the car after skidding to a stop on the icy patch.
A car is traveling on a straight, level road under wintry conditions. Seeing a patch of ice ahead of her, the driver of the car slams on her brakes and skids on dry pavement for 70 m, decelerating at 6.0 m/s2. Then she hits the icy patch and skids again. The car takes a duration of 85.0 s to come to rest during the second skid. If her initial speed was 50 m/s, what was the magnitude of the deceleration on the ice during the second skid.
A bicycle, initially located xo = 2.3 m at time t=0 seconds, has a velocity at time t given by %3D v = 1.6 t3 + 5.6 t with v in m/s and t in seconds. What is the position x (in meters) and the acceleration a (in m/s-) of the bicycle at time t? O x= 0.53 t + 5.6 t2 + 2.3 a = 4.8 t2 + 5.6 O x = 0.4 t + 2.8 t2 + 2.3 a = 4.8 t2 + 2.3 O x = 4.8 t2 + 5.6 a = 0.4 t + 2.8t + 2.3 O x= 4.8 t2 + 2.3 a = 0.4 t + 2.8 t2 + 2.3 Ox = 0.4 t + 2.8 t2 + 2.3 a = 4,8 t2 + 5.6
An object is thrown upward with an initial velocity of 17.3 m/s from a location where the acceleration due to gravity has magnitude g = 9.79 m/s². Assuming it moves in "free fall", the object moves upward what distance before starting to return downward? Give your answer, in meters, with appropriate significant figures.
The position of a particle is given by r(t) = (3.0 t2 ˆi+ 5.0 ˆj − 6.0 t ˆk) m. (a) What is its speed at t = 1 s and t = 3 s? (b) What are the average velocity and acceleration between t = 1 s and t = 2 s?
A woodpecker's brain is specially protected from large accelerations by tendon-like attachments inside the skull. While pecking on a tree, the woodpecker's head comes to a stop from an initial velocity of 0.600 m/s in a distance of only 2.00 mm. Find the acceleration in meters per second squared and in multiples of g, where g = 9.80 m/s².
The position of a particle as a function of time is given by x (1.7 m/s)t + (-3.2 m/s2)t. (a) Plot x-versus-t for time from t - 0 to t 1.0 s. (b) Find the average velocity of the particle from t = 0.45 s to t = 0.55 s. m/s (c) Find the average velocity from t = 0.49 s to t = 0.51 s. m/s