A woman lifts her 13 -newton child up 3 meters and carries her for a distance of 10 meters to the child’s bedroom. How much work does the woman do?

The child is given to have a weight of 13 N. $Let W=13 N$

This child is being lifted by their mother, from the ground, up to a distance of 3 meters straight up, after which the women walks straight 10 meters to the child's bedroom.

Now, there are two activities being done here, first is the lifting of the child, straight up, next is carrying the child horizontally to their room.

The work done against any force for a given displacement is given by the equation

$$\begin{gathered} W=Fd\cos \theta \\ F is the applied force \\ d is the dis\tan ce moved \\ \theta is the angle between the force and the resulting displacement \end{gathered}$$