A wide, thin slab of honey is flowing at a constant speed down a plane surface inclined at angle 0. Parameter values are listed below. Angle: Thickness: 0 = 20° H = 0.1m Width (into page)W=1m Length Density Viscosity L=2m PH=1450 kg/m3 HH= 40 N s/m². T=0 plate What is the component of the weight of the honey in the x-direction, parallel to the inclined plane? weight (x) = g sin0 = 9.81 * sin(20°) = 3.36 N || What is the stress (Tp) that the plate exerts on the base of the honey slab?

A wide, thin slab of honey is flowing at a constant speed down a plane surface inclined at angle 0. Parameter values are listed below. Angle: Thickness: 0 = 20° H = 0.1m Width (into page)W=1m Length Density Viscosity L=2m PH=1450 kg/m3 HH= 40 N s/m². T=0 plate What is the component of the weight of the honey in the x-direction, parallel to the inclined plane? weight (x) = g sin0 = 9.81 * sin(20°) = 3.36 N || What is the stress (Tp) that the plate exerts on the base of the honey slab?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Fast pls i will give u like for sure solve this question correctly in 5 min pls Consider a solid bar of length L with variable cross-sectional area given by A(x) , where x ∈ [0, L] is distance along the bar. If the sides of the bar are insulated and if A(x) varies slowly, it is reasonable to make an approximation in which the heat flows only in the x direction. Consider the rate of change of the total thermal energy between arbitrary positions x = a and b to derive a heat equation for the bar in terms of the temperature u(x, t) . You may assume the density, heat capacity and thermal conductivity are constant (i.e. constant thermal properties) and that there is no heat source.
An incompressible fluid (kinematic viscosity, 7.4 x10-7 m²/s, specific gravity, 0.88) is held between two parallel plates. If the top plate is moved with a velocity of 0.5 m/s while the bottom one is held stationary, the fluid attains a linear velocity profile in the gap of 0.5 mm between these plates; the shear stress in Pascals on the surface of top plate is rt of this book may be repro
QA An incompressible fluid (kinematic viscosity, 7.4 x10-7 m2/s, specific gravity, 0.88) is held between two parallel plates. If the top plate is moved with a velocity of 0.5 m/s while the bottom one is held stationary, the fluid attains a linear velocity profile in the gap of 0.5 mm between these plates; the shear stress in Pascals on the surface of top plate is (a) 0.651 x 10-3 (c) 6.51 (b) 0.651 (d) 0.651 x 103
(2) Referring to the following figure, the distance between plates is Ay = 0.5 cm, Av, 10 cm/s, and the fluid is ethanol at 273 K having a viscosity of 1.77cp (0.0177 g/cm s). dv:| ay (a) Calculate the shear stress Tyz and the velocity gradient of shear rate using cgs units. (b) (c) Repeat using SI units. Ay F, force Fluid shear between two parallel plates.
A fluid passes passes through a pipe with the following condition Fluid: - 1.61 x 10-4 Kinematic Viscosity Density - 2*/ma Specific Heat = 30 000 '/rg K Pipe: Inner Diameter = 50 mm Outer Diameter = 60mm Length = 11 m 3D Thermal conductivity = 17 "/mx Heat Transfer coefficient of water = 99 Compute for Prandit and Nusselt Number
The velocity distribution in a 0.02 m diameter horizontal pipe conveying carbon tetrachloride (specific gravity = 1.59, absolute viscosity = 9.6 x 10-6 Pa sec) is given by the parabolic equation: v(r)=0.01(0.12- r?), where v(r) is the velocity in (m/s) at a distance r in (m) from the pipe center. What is discharge? O a. 3.13 x-8 m3/s O b. None of the mentioned O c. 1.047 x 108 m3/sec O d. 4.97 x 109 m3/sec
What is the dynamic viscosity of the fluid? must include FBD F ... F = 0.45 Ibf m = 151 g v = 0.006 m/s Thk. = 20 cm THISE AN 8mm 6mm, A Steel Plate is pulled up at a constant QU velocity between two layers of liquid 30 cm Ignore Friction at openings @ 20°C @ 20°C 1940
1 ] Water flow through a pipe with diameter dwater = 0.05 m with a velocity of Vwater = 2 m/s, while oil flows through a parallel pipe with a velocity Voil = 8 m/s. Determine the diameter of the oil pipe (doil= ?) so that both fluids have the same dynamic characteristics. The temperature of the water and oil is 20°C. Properties: For the fluids at T = 20°C, poil = 880 kg/m³, pwater = 998.3 kg/m³, oil = 30.2x10-³ Ns/m² and water = 1.00×10³ Ns/m². 50 mm D
An incompressible fluid (kinematic viscosity, 7.4 x10-7 m²/s, specific gravity, 0.88) is held between two parallel plates. If the top plate is moved with a velocity of 0.5 m/s while the bottom one is held stationary, the fluid attains a linear velocity profile in the gap of 0.5 mm between these plates; the shear stress in Pascals on the surface of top plate is (a) 0.651 x 10-3 (c) 6.51 (b) 0.651 (d) 0.651 x 103
What is the behavior of flow if water at 20 deg C is flowing through a pipe with a radius of 2.067 in at 20 gal/min. Viscosity of water at 20 deg C =1.005 cP Density of water at 20 deg C = 998.23 kg/m3
(b) In two dimensional boundary layer, shear stress was changed linearly from the solid surface toward y-axis until it reach the value of zero at y = ở. Based on Table 2 and setting given to you; (i) Derive the equation of displacement thickness and momentum thickness using Von Karman Approximation Method ; and (ii) Determine the accuracy of this method in determining the value of displacement thickness and momentum thickness. C5 Table 2: Equation of Velocity Profile Setting Equation wU = 2y/8 - (y/S² 1
1) The velocity profile of a viscus fluid over a plate is parabolie with vertex 25 em from the plate ,where the velocity 125 cm/s. calculate the velocity gradient and shear stress at distance of (0, 5, 15 and 25 cm) from the plate given the viscosity of the fluid =7 poise ? Also draw the figure explain the relationship between the velocity gradient and shear stress. Take velocity profile for parabolic equation, (v = ay + by + c)