College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A wheel starts from rest and rotates with constant
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- A dentist's drill starts from rest. After 4.30 s of constant angular acceleration it turns at a rate of 2.05 ✕ 104 rev/min. (a) Find the drill's angular acceleration. rad/s2(b) Determine the angle (in radians) through which the drill rotates during this period.arrow_forwardA dentist's drill starts from rest. After 3.10 s of constant angular acceleration it turns at a rate of 2.70 ✕ 104 rev/min. (a) Find the drill's angular acceleration. (b) Determine the angle (in radians) through which the drill rotates during this period.arrow_forwardA 41.0-cm diameter disk rotates with a constant angular acceleration of 3.00 rad/s2. It starts from rest at t = 0, and a line drawn from the center of the disk to a point P on the rim of the disk makes an angle of 57.3° with the positive x-axis at this time. (a) At t = 2.44 s, find the angular speed of the wheel. ?rad/s(b) At t = 2.44 s, find the magnitude of the linear velocity and tangential acceleration of P. linear velocity ?m/s tangential acceleration ? m/s2 (c) At t = 2.44 s, find the position of P (in degrees, with respect to the positive x-axis). ° counterclockwise from the +x-axisarrow_forward
- A ball of radius0.226 m rolls along a horizontal tabletop with a constant linear speed of 5.36 m/s. The ball rolls off the edge and falls a vertical distance of 2.47 m before hitting the floor. What is the angular displacement of the ball while it is in the air? Use g=9.8arrow_forwardThe angular speed of a rotating platform changes from ω0 = 2.6 rad/s to ω = 8.8 rad/s at a constant rate as the platform moves through an angle Δθ = 4.5 radians. The platform has a radius of R = 44 cm. Calculate the angular acceleration of the platform α in rad/s2.arrow_forwardThe angular speed of a wheel decreases uniformly from 34.0 rad/s to 2.0 rad/s in 18.0 s.A. Find the constant angular acceleration in rad/s^2.B. Find the number of revolutions made by the wheel in this time.arrow_forward
- A tire is rotating at an angular velocity of 51.6 radians/s. The radius of the tire is 1.9 m. Find the linear speed/velocity of a point on the edge of the tire.arrow_forwardQUESTION 2 Which of the following is an accurate statement? O A. It is possible to add a scalar quantity to a vector. O B. Even though two vectors have unequal magnitudes, it is possible that their vector sum is zero. OC. Rotating a vector about an axis passing through the tip of the vector does not change the vector. OD. The magnitude of a vector is independent of the coordinate system used. O E. The magnitude of a vector can be zero even though one of its components is not zero.arrow_forwardA helicopter propeller blade starts from rest and experiences a constant angular acceleration of 25.0 rad/s2. Find the speed of a point on the blade 2.70 m from the axis of rotation when the blade has completed 20 revolutionsarrow_forward
- A wheel 2 m in diameter lies in a vertical plane and rotates with a constant angular acceleration of 4 rad/s2. The wheel starts at rest at t =0, and the radius vector of point P on the rim makes an angle of 57.3o with the horizontal at this time. At t=2s, find the angular speed of the wheelarrow_forwardThe wheels of a bicycle (radius 40 cm ) have an angular velocity of 17 rad/s before the brakes are applied. In coming to rest, each wheel rotates through an angular displacement of 7 revolutions. Part A How long did it take for the bicycle to come to rest? ΑΣφ ? S Submit Request Answer Part B How far did the bicycle travel while it was stopping? ην ΑΣφ ? m Submit Request Answerarrow_forwardA rotating wheel requires 4.66 s to rotate through 45.9 rev. It’s angular speed at the end of the 4.66s interval is 66.2 rad/s. What is its constant angular acceleration? Assume the angular acceleration has the same sign as the angular velocity. Answer in units of rad/s^2.arrow_forward
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