A wheel (radius 0.350 m) starts from rest and rotates with a constant angular acceleration of 2.20 rad/s2. At the instant when the angular velocity is equal to 1.30 rad/s, what is the magnitude of the total linear acceleration (in m/s2) of a point on the rim of the wheel? Round your answer to 2 decimal places.
Angular speed, acceleration and displacement
Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.
Angular Position
Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.
A wheel (radius 0.350 m) starts from rest and rotates with a constant
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
