(a) What is the capacitance of a parallel plate capacitor having plates of area 1.5 m² that are separated by 0.023 mm of neoprene rubber (K = 6.7)? C = HF (b) What charge does it hold when 8.5 V is applied to it? Q = C (c) Compare this charge to the case when no dielectric is present. The charge when no dielectric is present is is present. Q dielectric Qno - dielectric = compared to when a dielectric

Consider a cylindrical condenser where between the concentric surfaces a dielectric with relative permittivity epsilon_r = (r/a)^2. The inner surface has radius a = 2.3 cm, the surfaces exterior has radius b = 8.1 cm and length L =6.4cm. The surface interior has charge q = 2.7 x 10^(-3) C and the exterior surface is connected the land.   Calculate the potential difference between the condenser surfaces in SI units?

A parallel plate capacitor is constructed with plates of areas 0.038 m² and separation 0.6 mm. (a) Calculate capacitance of the capacitor( in pF)? (b) Find the magnitude of the charge (in nC) on each plate of this capacitor when the potential difference between the plates is 48.2 V

(a) How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 6.00 cm2? (Assume air has a dielectric strength of 3.00 ✕ 106 V/m and dielectric constant of 1.00.) nC(b) Find the maximum charge if bakelite is used between the plates instead of air. (Assume bakelite has a dielectric strength of 24.0 ✕ 106 V/m and dielectric constant of 4.9.) nC

How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 6.00 cm2? Find the maximum charge if bakelite is used between the plates instead of air.

Question 17 ( The effective area of each plate of a parallel plate capacitor is 2.1 m2. The capacitor is filled with neoprene rubber (k = 6.4). When a 6.0-V potential difference exists across the plates of the capacitor, the capacitor stores 4.0 µC of charge. a) What is the capacitance of the capacitor? (-. b) Determine the plate separation of the capacitor.(

A certain capacitor has a capacitance of 4μF when its plates are separated by 0.2 mm of vacant space. A battery is used to charge the plate to a potential difference of 500 V and is then disconnected from the system. (a) What will be the potential difference across the plates if a sheet of mica 0.2 mm thick is inserted between the plates? (b) What will the capacitance be after the dielectric is inserted? (c) What is the permittivity of mica?

(a)What is the capacitance of a parallel plate capacitor having plates of area 1.50 m2 that are separated by 0.0200 mm of neoprene rubber?                      (b) What charge does it hold when 9.00 V is applied to it?

A parallel plate capacitor has plate each of length 20.0 cm and breadth 10.0 cm. The separation between the plates is 1 mm. Calculate The potential difference between the 3 plate if charge of 1 nC is given to capacitor. (b) With the same charge of 1 nC, if the separation between plates is doubled, what is the new potential differences ? (c) electric field between the plates