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A whale travels 25.0 km [E 30° N] and then moves 45.0 km [N 43.0° W]. What is the total displacement of the whale?

A whale travels 25.0 km [E 30° N] and then moves 45.0 km [N 43.0° W]. What is the total displacement of the whale?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Kindly provide the solution to the following question using the GRASS method: 

A whale travels 25.0 km [E 30° N] and then moves 45.0 km [N 43.0° W]. What is the total displacement of the whale?

 

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tiver: Ad Ad Required: Ad Ad Ad Y Anclysis: Let mooth & west be positive tv 4d² = Ad + Ad 2 Sektion: N (20.0km) (sin 25°) (20.0xmXcos 25°) (45.0 kyksin 40) X WE (45.0km) (cos 40.00) 40.0⁰ Ad Ad + Ad Bd² = (-20.0kn) (co₁ 250) + (45.0 kn)(sin 40.0°) bota = 10.799 km Ad = A + Act Ady = (20.0 km.) (sin 250) + (45.0 kn X(cos 40.0") Ady = [42.924 km] | AZ²₂1 = √(40₂)² + (Ad4₂) ² 142, 1 =√ √/(10.799 kn)² + (42.924 kn)² 1Ad1=44.262 km Scheton (contid): - O + tan" (Ads) ở bán 42.921 km -1 10.799 Kn 0 = 75.9° Statene ti Then fore, the displacement of the whole is 4.43 x 10¹ kn [W76″N
Transcribed Image Text:tiver: Ad Ad Required: Ad Ad Ad Y Anclysis: Let mooth & west be positive tv 4d² = Ad + Ad 2 Sektion: N (20.0km) (sin 25°) (20.0xmXcos 25°) (45.0 kyksin 40) X WE (45.0km) (cos 40.00) 40.0⁰ Ad Ad + Ad Bd² = (-20.0kn) (co₁ 250) + (45.0 kn)(sin 40.0°) bota = 10.799 km Ad = A + Act Ady = (20.0 km.) (sin 250) + (45.0 kn X(cos 40.0") Ady = [42.924 km] | AZ²₂1 = √(40₂)² + (Ad4₂) ² 142, 1 =√ √/(10.799 kn)² + (42.924 kn)² 1Ad1=44.262 km Scheton (contid): - O + tan" (Ads) ở bán 42.921 km -1 10.799 Kn 0 = 75.9° Statene ti Then fore, the displacement of the whole is 4.43 x 10¹ kn [W76″N
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