A well-known brokerage firm executive claimed that at least 55 % of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that out of 58 randomly selected people, 30 of them said they are confident of meeting their goals. Suppose you are have the following null and alternative hypotheses for a test you are running: Ho:p = 0.55 Ha:p + 0.55 Calculate the test statistic, rounded to 3 decimal places Z =

Suppose that the proportion of investors who are risk-averse (that is, try to avoid risk in their investment decisions) is though to be at least 0.6. A financial advisor believes that the proportion is actually less than 0.6. A survey of 28 investors found that 16 of them were risk-averse. Formulate a one-sample hypothesis test for a proportion to test this belief. Determine the null hypothesis, Ho, and the alternative hypothesis, H₁. Ho 2 0.6 H₁ 0.6 (Type integers or decimals. Do not round.) Compute the test statistic. (Round to two decimal places as needed.) 4 D

According to a University Center for Logistics Management, 12% of all merchandise sold in the United States gets returned. A Seattle department store sampled 89 items sold in January and found that 8 of the items were returned.If you have the following null and alternative hypotheses for a test you are running:H0:p=0.12Ha:p<0.12Calculate the test statistic, rounded to 3 decimal places Z=

You may need to use the appropriate appendix table or technology to answer this question. A survey asked senior executives at large corporations their opinions about the economic outlook for the future. One question was, "Do you think that there will be an increase in the number of full-time employees at your company over the next 12 months?" In the current survey, 228 of 400 executives answered Yes, while in a previous year survey, 176 of 400 executives had answered Yes. Provide a 95% confidence interval estimate for the difference between the proportions at the two points in time. (Use current year previous year. Round your answer to four decimal places.) to What is your interpretation of the interval estimate? The 95% confidence interval ---Select--- ✓zero. This suggests that the proportion of executives who are predicting an increase in full- time jobs for the current year is ---Select--- ✓ than the proportion of executives who were predicting an increase in full-time jobs for the…

A well-known brokerage firm executive claimed that at least 86 % of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that out of 61 randomly selected people, 50 of them said they are confident of meeting their goals.Suppose you are have the following null and alternative hypotheses for a test you are running:H0:p=0.86Ha:p≠0.86Calculate the test statistic, rounded to 3 decimal places

A local coach wants to see if training in light rooms or dark rooms impacts athlete performance. With the single team, the coach tries training in different conditions and takes measurements. She ran her analysis in Microsoft Excel and received the following output table. If the P value is less than 0.05, the null hypothesis may be rejected. Based on the data table, what decision should the coach make about the hypothesis?                  Coach should reject the null hypothesis.   Coach should fail to reject the null hypothesis.     Coach should accept the null hypothesis.    Coach does not have enough information to decide.

A well-known brokerage firm executive claimed that at least 24 % of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that out of 150 randomly selected people, 42 of them said they are confident of meeting their goals. Suppose you are have the following null and alternative hypotheses for a test you are running: Ho:p = 0.24 Ha:p + 0.24 Calculate the test statistic, rounded to 3 decimal places

It has been reported in the past that the probability that an individual will develop schizophrenia over their lifetime is 0.004. A researcher believes that this proportion has increases since then. She found out that in a random sample of 2500 individuals, 16 developed schizophrenia. Is there evidence to support the claim that the true proportion of people who will develop schizophrenia is greater 0.004? Use hypothesis testing at a = 0.10 level of significance to answer this question. a. State the null and alternative hypotheses. b. What is the probability model (underlying distribution of the sample proportion p)? c. Compute p. d. Compute the test statistic. e. Find the P-value. f. Make the decision whether to reject Ho or not. g. State a conclusion answering the question above. 1

According to the Centers of Disease Control, about 22% of American young people between the ages of 12 and 19 are obese.A student claims that the students in his local schools are in better shape than the national average, so their proportion of obese students is less than 22%. Which are the appropriate null and alternative hypotheses for this study? H0: p = 22%, HA: p < 22% H0: p ≠ 0, HA: p = 0 H0: p = 22%, HA: p > 22% H0: p = 22%, HA: p ≠ 22% Suppose that the result is to Fail to reject H0.Which is the proper conclusion? There is sufficient evidence to support the claim that the students at his local schools have a smaller proportion of obese students. There is not enough information to answer this question. There is not sufficient evidence to support the claim that the students at his local schools have a smaller proportion of obese students.

A December 2017 Gallup Poll reported that 43% of Americans use the internet for an hour or more each day. You suspect that a greater proportion of students at your school use the internet that much. You take a random sample of 60 students and find that 36 of them use the internet for an hour or more each day. Assume your school has more than 600 students. You will test the hypotheses H, : p = 0.43, H,:p>0.43 , where p= the true proportion of students at your school who use the internet for an hour or more each day. Which of the following gives the correct test statistic for this test? 0.43 - 0.6 Z = (0.6)(0.4) 60 0.43-0.6 (0.6)(0.4) 600 0.6-0.43 (0.6)(0.4) 60 0.6 - 0.43 (0.43)(0.57) 60 36 - 60 (36)(24) 60