A wastewater treatment facility needs to install a sedimentation tank as part of their operations. There are two options for the design of the tank, namely a circular tank with a diameter of 5m or a rectangular tank with a square area, with a length of 5m. a) Determine the cost needed for each case given that the water supply is 1,500 m'/d of which 25% is lost to evaporation before entering the tank, and the detention time is 2 hours. Cost vs. height of sedimentation tank 4 3. 20000 40000 60000 80000 100000 120000 140000 160000 Cost (USD) b) Discuss the advantages and/or disadvantages of the different shapes of the sedimentation tanks focusing on construction and maintenance. Height of sedimentation tank (m}

A wastewater treatment facility needs to install a sedimentation tank as part of their operations. There are two options for the design of the tank, namely a circular tank with a diameter of 5m or a rectangular tank with a square area, with a length of 5m. a) Determine the cost needed for each case given that the water supply is 1,500 m'/d of which 25% is lost to evaporation before entering the tank, and the detention time is 2 hours. Cost vs. height of sedimentation tank 4 3. 20000 40000 60000 80000 100000 120000 140000 160000 Cost (USD) b) Discuss the advantages and/or disadvantages of the different shapes of the sedimentation tanks focusing on construction and maintenance. Height of sedimentation tank (m}

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Q.5 Sedimentation Basin/Tank: Two million liters of wastewater per day is passing through a sedimentation tank which is 6 m wide, 15 m long and having a water depth of 3 m. Find: (i) Detention time for the tank, (ii) The average flow velocity through the tank, (iii) The surface overflow rate (SOR), (iv) Amount of sludge that will be generated per day in the tank if influent TSS concentration is 300 mg/L. Assume 70% removal of solids in the basin and average specific gravity of the deposited solids as 2.0.
A wastewater treatment plant will receive a flow of 30,000 m3/day. The plant has a 3.6 m deep circular primary clarifier with a surface overflow rate of 60.0 m3/m2-day.a. Calculate the surface area (m2), diameter (m), volume (m3), and hydraulic retention time of the primary clarifier.b. How long will it take a 1.0 mm particle with a density of 1500 kg/m3to settle in the primary clarifier? show all work
A municipal wastewater treatment plant uses a circular clarifier. It receives 12 million gallons per day of wastewater. The clarifier radius is 25 ft and the depth is 29 ft. What is the detention time in the clarifier? What is the overflow rate? (1 cubic foot = 7.48 gallons)
A treatment unit is 7.0m wide, 25m long and has a depth of 3.5m. If the wastewater flow rate through the tank is (13500) gallons per day. Calculate: 1. Hydraulic detention time 2. Surface loading rate
3. Consider the design of a wastewater treatment plant (WWTP) for a community with the following design data: TABLE 1: Design Data Design data Flow-0.150m³. s-¹ Influent suspended solids=280mg L-¹ Influent BODs = 500mg L-¹ Sludge concentration=6.0% Efficiency= 60% Effective length= 40.0 m Width 10.0 m Liquid depth = 2.0 m Weir length= 75.0 m Table 2: Acceptability Criteria Parameter Detention time (hours) Overflow rate (m- day Weir loading (m³-day"¹ m²') Acceptable range 1.5-2.5 80-120 <250 (a) Using a clearly annotated diagram, describe the major processes in a tertiary level wastewater treatment plant.
Question- A circular primary clarifier processes an average flow of 3000 m³/d of municipal wastewater. The overflow rate is 25 m³/d. Find the diameter of clarifier.
The 750-bed Associated Center of Medical Excellence (ACME) Hospital has a small activated sludge plant to treat its wastewater. The average daily Medical Center discharge is 1,250 L per day per bed, and the average soluble BOD5 after primary settling is 450 mg/L. The aeration tank has effective liquid dimensions of 10.0 m wide by 25.0 m long by 3.5 m deep. The plant operating parameters are as follows: MLVSS = 2,750 mg/L MLSS = 1.25 (MLVSS) Settled sludge volume after 30 min = 250 mL/LDetermine the following: aeration period, F/M ratio, SVI, solids concentration in return sludge.
3. Consider the design of a wastewater treatment plant (WWTP) for a community with the following design data: TABLE 1: Design Data Design data Flow-0.150m³. s-¹ Influent suspended solids-280mg L-¹ Influent BODs = 500mg L-¹ -1 Sludge concentration= 6.0% Efficiency= 60% Effective length= 40.0 m Width = 10.0 m Liquid depth = 2.0 m Weir length= 75.0 m Table 2: Acceptability Criteria Parameter Detention time (hours) Overflow rate (m- day) Weir loading (m³-day m¹') Acceptable range 1.5-2.5 80-120 <250 (c) Assume that the primary sedimentation process in this treatment facility removes 60% of the suspended solids (SS) and 40% of the BODs of the raw sewage. Determine the SS and BOD5 concentrations in the primary sedimentation effluent flow.
The dimensions of a rectangular settling tank are : length 24 m, width 6 m and depth 3 m. If 2 hour detention period for tanks is recommended, the rate of flow of sewage per hour, is * O 204 m^3 O 216 m^3 O 208 m^3 O 212 m^3
A conventional activated-sludge system treats 11,000 m3/day of wastewaterin an aeration tank with a volume of 3400 m3. The BOD after primary clarification is 180mg/l. Given the operation conditions below, calculate the sludge residence timeMLVSS in the rector = 2,100 mg/lMLSS = (1.25)*MLVSSQw = 160 m3/daySVI = 125 mL/g (Ans. SRT = 7.0 days)
A sewage treatment plant contains fourteen standard rate tricking filters with diameter 37.8m filters, and two secondary Jarifiers with diameter 18.2m. Calculate the maximum allowable output capacity of the treatment plant using the following data: . BOD of raw sewage 300 mg/L. . BOD removal in primary sedimentation 30% . BOD effluent 35 mg/L • Overall efficiency of BOD removal 90%
a) An industry has decided to treat its process wastewater in a biotower with a plastic modular medium (n = 0.55). The flow rate of the wastewater is 1400 m3 /d with a BOD5 of 630 mg/l. Average summer and winter temperatures are 22°C and 15°C, respectively. The treatability constant is 0.04 min–1 for the system at 20°C. Depth of the medium is 4 m. Calculate the area of the biotower required to produce an effluent with a BOD5 of 20 mg/l, with a recycle ratio of 2:1. b) Rework problem a) using a winter recirculation ratio of 3:1.Summer recirculation ratio remains the same at 2:1. Comment onthe pros and cons of using a higher recirculation ratio