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A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 7 m long, fixed at the top and bottom, and has additional support in the weak direction 3 m from the top. Properties of the section are: A = 14,500 mm² , Ix = 258.6 x 10° mm“, I, = 84.375 x 10° mm* X 1. Calculate the critical slenderness ratio of the member. A. 26.208 С. 36.706 В. 45.882 D. 27.529 Calculate the nominal axial load capacity of the column. A. 3 104 kN C. 4 213 kN 2. B. 4 851 kN D.5 344 kN

A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 7 m long, fixed at the top and bottom, and has additional support in the weak direction 3 m from the top. Properties of the section are: A = 14,500 mm² , Ix = 258.6 x 10° mm“, I, = 84.375 x 10° mm* X 1. Calculate the critical slenderness ratio of the member. A. 26.208 С. 36.706 В. 45.882 D. 27.529 Calculate the nominal axial load capacity of the column. A. 3 104 kN C. 4 213 kN 2. B. 4 851 kN D.5 344 kN

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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NSCP 2015 Pn = FerAg (505.3-1) The flexural buckling stress, Fer, is determined as follows: cr 5 KL 1. when E < 4.71 (or Fe 2 0.44F,) r Fy Fer = 0.658Fe| Fy (505.3-2) KL E > 4.71 ( or F. < 0.44F,) 2. when - r Fer = 0. 877F. (505.3-3) %3D where ,= elastic critical buckling stress determined according to Eq. 505.3-4, Section 505.4, or the provisions of Section 503.2, as applicable, MPa. e Fe (KL (505.3-4) (学) 2 A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 7 m long, fixed at the top and bottom, and has additional support in the weak direction 3 m from the top. Properties of the section are: A = 14,500 mm² , Ix = 258.6 x 10° mm“, I, = 84.375 x 106 mm4 1. Calculate the critical slenderness ratio of the member. В. 45.882 A. 26.208 С. 36.706 D. 27.529 Calculate the nominal axial load capacity of the column. A. 3 104 kN C. 4 213 kN 2. B. 4 851 kN D.5 344 kN 3. Calculate the service axial dead load if the service axial live load is twice as that of the dead load. Use LRFD. В. 992 kN D. 634 kN A. 1 354 kN C. 1 093 kN
Transcribed Image Text:NSCP 2015 Pn = FerAg (505.3-1) The flexural buckling stress, Fer, is determined as follows: cr 5 KL 1. when E < 4.71 (or Fe 2 0.44F,) r Fy Fer = 0.658Fe| Fy (505.3-2) KL E > 4.71 ( or F. < 0.44F,) 2. when - r Fer = 0. 877F. (505.3-3) %3D where ,= elastic critical buckling stress determined according to Eq. 505.3-4, Section 505.4, or the provisions of Section 503.2, as applicable, MPa. e Fe (KL (505.3-4) (学) 2 A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 7 m long, fixed at the top and bottom, and has additional support in the weak direction 3 m from the top. Properties of the section are: A = 14,500 mm² , Ix = 258.6 x 10° mm“, I, = 84.375 x 106 mm4 1. Calculate the critical slenderness ratio of the member. В. 45.882 A. 26.208 С. 36.706 D. 27.529 Calculate the nominal axial load capacity of the column. A. 3 104 kN C. 4 213 kN 2. B. 4 851 kN D.5 344 kN 3. Calculate the service axial dead load if the service axial live load is twice as that of the dead load. Use LRFD. В. 992 kN D. 634 kN A. 1 354 kN C. 1 093 kN
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