A violin string is 36.0 cm long. It sounds the musical note A (440 Hz) when played without fingering. For help with math skills, you may want to review: Proportions For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Palm pipes. Part A How far from the end of the string should you place your finger to play the note C (523 Hz

Item 7 Learning Goal: To understand the concept of intensity; the relationship between the power of the source and the intensity of the wave; and the dependence of intensity on distance. Since waves transfer energy from one point to another, one can define the power of a wave as the rate at which the wave transports energy. The intensity of a wave, in contrast, is the power relative to a certain surface. Consider a wave traveling across a surface perpendicular to the direction of propagation. The intensity I of the wave is defined as the ratio of the power P of the wave to the area A of that surface: P I= R Note that the surface may be real (physical, like an eardrum or a windowpane) or mathematical. Quite frequently, we will be interested in the intensity produced by a relatively small source at a relatively large distance. If the source emits waves uniformly in all possible directions (produces spherical waves), the formula given here makes it possible to find the intensity at a…

A Ferris wheel has a radius of 20 metres. The minimum height of the wheel is 3m above the ground. If the wheel makes one full revolution every  seconds and you start observing a friend when they are at the lowest point of the wheel:    a) Sketch the graph of one full cycle of the situation given.    b) Determine the height of your friend after  seconds.   c) Determine when the height of your friend is 18 metres.

Item 6 Learning Goal: To understand standing waves, including calculation of X and f, and to learn the physical meaning behind some musical terms. The columns in the figure (Figure 1) show the instantaneous shape of a vibrating guitar string drawn every 1 ms. The guitar string is 60 cm long. The left column shows the guitar string shape as a sinusoidal traveling wave passes through it. Notice that the shape is sinusoidal at all times and specific features, such as the crest indicated with the arrow, travel along the string to the right at a constant speed. The right column shows snapshots of the sinusoidal standing wave formed when this sinusoidal traveling wave passes through an identically shaped wave moving in the opposite direction on the same guitar string. The string is momentarily flat when the underlying traveling waves are exactly out of phase. The shape is sinusoidal with twice the original amplitude when the underlying waves are momentarily in phase. This pattern is called a…

A spool of wire 150 m long has a mass of 0.190 kg when weigh on a scale. This string is used to set up a standing wave laboratory demonstration between two posts 3.0 m apart. Part A If the desired second harmonic frequency is 75 Hz, what should be the required string tension? Express your answer using two significant figures. Fr= hmit Benunst Answer N

In a certain home sound system, two small speakers are located so that one is 80.0 cm closer to the listener than the other. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of interference from two loudspeakers. Part A For what frequencies of audible sound will these speakers produce destructive interference at the listener? (Find only the three lowest audible frequencies.) Express your answer(s) in hertz, if there is more than one value, separate your answers by commas. ? Hz Submit Request Answer Part B For what frequencies of audible sound will these speakers produce constructive interference at the listener? (Find only the three lowest audible frequencies). Express your answer(s) in hertz, if there is more than one value, separate your answers by commas. Πνα ΑΣφ ? f = Hz Submit Request Answer

A 62.5-Hz sound wave is barely audible at a sound intensity level of 60.0 dB. The density of air at 20.0°C is 1.20 kg/m3. Speed of sound in air at 20.0°C is 343 m/s. What is the displacement amplitude of a 62.5-Hz sound wave? in nm What is the ratio of the displacement amplitude to the average distance between molecules in air at room temperature, about 2.00 nm?

Draw schematics of the configurations shown but replace the molecular bonds with springs: each bond has a spring constant (kn) and each molecule has a mass (mn). Describe how you might develop a model for calculating the resonant frequency for each of the three molecular configurations (you don’t have to work out the math!). This model describes “acoustic phonons”.

Part C The power in the speaker from Part A is doubled, bringing the sound intensity to 2 × 10-6 W/m². This leads to 3 = 10 log (2 × 106). Which of the following equations is equivalent to log (2 × 106)? O log(2) × log (106) O log(2) + log (106) 2x log (106) 2 + log (106) O log (106) +log (106) O 6 × log(20) Submit Request Answer Part D Complete previous part(s)

A certain organ pipe, open at both ends, produces a fundamental frequency of 275 Hz in air. Part A If the pipe is filled with helium at the same temperature, what fundamental frequency fHe will it produce? Take the molar mass of air to be 28.8 g/mol and the molar mass of helium to be 4.00 g/mol. Express your answer in hertz. ► View Available Hint(s) fHe = 806 Hz Submit Previous Answers Correct Correct answer is shown. Your answer 805.9 Hz was either rounded differently or used a different number of significant figures than required for this part. Because helium is less dense than air and has a lower molar mass, sound waves propagate faster in helium than in air. Thus, the frequencies produced in the pipe when it is filled with helium are higher than those produced in the same pipe filled with air. Part B Now consider a pipe that is stopped (i.e., closed at one end) but still has a fundamental frequency of 275 Hz in air. How does your answer to Part A, ƒHe, change? ► View Available…