a) Using the given set of balanced latitudes and departures, calculate the areas of the traverses using DMDS with the meridians through the most westerly point. b) Repeat using the double parallel distances (DPDS) method with the reference passing through the most northerly point. c) Repeat using the DPDS with the reference passing through the most southerly point. Balanced Latitudes Balanced Departures Side N S E W АВ 215 311 ВС 310 230 CD 224 270 DA 319 271

a) Using the given set of balanced latitudes and departures, calculate the areas of the traverses using DMDS with the meridians through the most westerly point. b) Repeat using the double parallel distances (DPDS) method with the reference passing through the most northerly point. c) Repeat using the DPDS with the reference passing through the most southerly point. Balanced Latitudes Balanced Departures Side N S E W АВ 215 311 ВС 310 230 CD 224 270 DA 319 271

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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2. AREA BY DMD. For the given sets of adjusted latitudes and adjusted departures shown in the accompanying tabulations, determine the area of each traverse (in sq.m. and ha.) using the double meridian distance method. ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE -w AB 7i5.20 1200.53 BC 414.29 401.78 CD 419.88 1606.43 1735.58 DE 200.70 EF 617.59 456.66 FG 849.91 202.83 GA 233.53 677.83 Sums +2383.40 -2383.40 +2482.97 -2482.97 ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE -S 1-2 281.28 281.06 2-3 168.75 449.32 3-4 337.56 281.22 4-5 112,50 450.66 450.03 225.08 5-6 6-1 450.06 335.86 Sums +900.09m-900.09 m+10I1.60MFIOT1.60m
AREA BY DMD. For the given sets of adjusted latitudes and adjusted departures shown in the accompanying tabulations, determine the area of each traverse (in sq.m. and ha.) using the double meridian distance method. ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE +N -S AB 7i5.20 1200.53 вс CD DE 401.78 414.29 1735.58 419.88 1606.43 456.66 200.70 EF 617.59 FG 849.91 202.83 GA 233.53 677.83 Sums +2383.40 -2383.40 +2482.97 -2482.97 ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE +N -S +E - w 281.06 1-2 2-3 281.28 168.75 449.32 337.56 281.22 T12,50 450.66 450.03 225.08 450.06 335.86 Sums +900.09 m 900.09 m+1011.60mHio11.6Om N3456- -2345
Q1. Calculate departures and latitudes of the following ABCDE traverse. 3 N A 285.40' •N26°10'E E 5 75 25 E 640.45' 647.02' 5306 W N 0°42' W 720.8 203.00 5 15 30¹ W
For the given sets of adjusted latitude and adjusted departure shown in the accompanying tabulation. Determine the area of each traverse using the double meridian distance method sume ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE -8 +E sece AB 715.20 1200.53 BC eed 401.78 CD 414.29 1735.56 419.60 1606.43 DE 200.70 EF 617.59 456.66 FG 849.91 202.63 GA 233.53 677.83 Sums 2383.40 -2383.40 +2482.97 -2482.97 ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE -8 +E 281.28 168.75 1-2 281.06 2-3 449.32 3-4 337.56 281.22 112.50 450.66 4-5 450.03 225.08 5-6 335.86 6-1 450.06 Sums +900.09m-900.09 m1011.60mI011.60m
From the following traverse notes, compute the corrected distance of line CD using Transit Rule. LINE BEARING DISTANCE LATITUDE DEPARTURE А-В N 15 30' E 60.00 m + 57.81 16.03 В-С S 82 23' E 72.69 9.63 72.04 S 17° 20' E - 42.79 C-D 44.83 13.36 D-E S 70 36' W 56.45 18.75 53.25 E-A N 74 20' W 50.00 + 13.50 48.14
PROBLEM 1. Given in the accompanying tabulation are the adjusted latitude and adjusted departure of a closed traverse. Calculate the area by the DMD method LINE ADJ ADJ LAT DEP AB - 125.055 + 196.387 BC +20.241 + 241.003 CD +180.107 + 65.326 DE +210.169 - 104.519 EF -74.003 - 260.516 FA - 211.459 - 137.681
Q7) Calculate the coordinates. Check whether the error is acceptable. Make corrections. N 59.0701g S2 145.5558g S1 161.51849 A x=315.122m $3 S6 120.6210g 167.8089g S4 F S5 Y (m) x (m) Дх B (grad) a (grad) S (m) Ay STATION A 137.619 214.077 170.542 D 189.664 225.219 F 156.907 A 8 y=74.056m
Using the previous exomple, bolance the departures and latitudes using the transit rule. Correer DEP (DEP of course) Corrur"ELAT (LAT of course) OEVALUATE Compute the area of the given traverse using DPD and DMD method. COURSE LENGTH (m) BEARING AB 495.85 NOS" 30' E BC 850.62 N 46° 02' E CD 855.45 S 67* 38 E DE 1020.87 S 12* 25 E EF 1117.26 S 83* 44' W FA 660.08 N 55" 09' W ERSITY
Direction: Given the following data on the table. Fill up the needed data. Balance the traverse by transit rule. Solve the area by DPD or DMD. Sketch the traverse. All values must be in decimal places. COMPUTED ADJUSTED DEPARTURE LIN ADJUST ADJUST DISTAN СЕ (M) AZIMUT COMPUTED ADJUSTED LATITUDE ADJUST ED AZIMUT BEARIN DPD DOUBLE E G LATITUDE DEPARTURE ED DISTAN СЕ ED AREA (from S) BEARIN H (nearest (nearest minute) minute) +NL -SL +ED -WD +NL -SL +ED -WD АВ E S 70-29 N 10-00 650.00 ВС 895.00 CD S 26-28 315.00 DE S 65-33 W EA 875.00 410.00 N 45-31 W ТОTAL LEC : RP (nearest hundred) AREA ..
Using the data below, compute for the Linear Error of Closure Also, Determine the adjusted latitude and departure using compass rule: Line Distance Latitude Departure Adjustment (Lat) Adjustment (Dep) Adjusted Lat Adjusted Dep 1-2 388.08 -234.363 -309.322 2-3 732.72 732.665 8.952 3-4 324.78 -22.938 323.969 4-1 477.24 -476.557 -25.531 Express all answer unitless and with 3 decimals for A to J Next
Compute for the corrected distance AB of the traverse shown using compass rule LINES BEARING DISTANCES АВ DUE NORTH 400 BC N 45° E 800 S 60° E S 20° W S 86°59' W CD 700 DE 600 EA 966.34 O 399.983 O 399.883 400.083 399.783
The accompanying tabulation are given the adjusted latitude and departures of a closed traverse. LINE | LATITUDE (m) DEPARTURE (m) АВ 490.71 47.27 BC 587.12 608.89 CD -327.41 786.78 DE -1002.76 218.32 EF -122.67 -1116.62 FA 375.01 -544.64 Calculate the area by the DPD Method in square meter. (Just input the magnitude only in two decimal places.