(a) Using Proposition 1.3.2 and/or the definition of absolute value, prove that if b ‡ 0, 1 1|2|= |b|` then (b) Prove that for all a E R and b = 0, we have |a| |b| a .

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.1: Real Numbers
Problem 38E
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proposition 1.3.2 ( 

Proposition 1.3.2. For any two real numbers x, y, we have
√₁² = |x|
|x|² = x²
2
x
≤ |x|
and
|x · y| = |x|·|y|.
Transcribed Image Text:Proposition 1.3.2. For any two real numbers x, y, we have √₁² = |x| |x|² = x² 2 x ≤ |x| and |x · y| = |x|·|y|.
(a) Using Proposition 1.3.2 and/or the definition of absolute value, prove that if b = 0,
1
then
| -
|b|
(b) Prove that for all a E R and b = 0, we have
b
a
b
-
|b|
Transcribed Image Text:(a) Using Proposition 1.3.2 and/or the definition of absolute value, prove that if b = 0, 1 then | - |b| (b) Prove that for all a E R and b = 0, we have b a b - |b|
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