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Question

Answer all parts of the physics problem please

A uniformly charged rod of length L is bent into an arc of radius R. Total charge on the rod is Q. This is similar to the arc problem we considered in class. (a) Find the angle in radians, 0, subtended by the arc and the linear charge density A in terms of Q, L and R. See the exercises and the hints and guide at the end of the homework for a reminder of the relationship between angle and arc length.
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Transcribed Image Text:A uniformly charged rod of length L is bent into an arc of radius R. Total charge on the rod is Q. This is similar to the arc problem we considered in class. (a) Find the angle in radians, 0, subtended by the arc and the linear charge density A in terms of Q, L and R. See the exercises and the hints and guide at the end of the homework for a reminder of the relationship between angle and arc length.
(b) Find the field at a test point placed at the center of the circle that the arc is part of. Again, follow the process, and remember that the sample charge dq occupies a small length of the rod, and that length is now a small part of an arc. (c) Check that your results for the case L << R give you the field of a point source with charge Q, a distance R away. You will want to use the small angle approximation from the exercises: sin 0 z 0 for 0 << 1 (d) With minimal reanalysis (just note where you need to change the work you did above and how that changes the result) find the field at the test point if we replace the charge on half the rod with the opposite charge, so we have +Q/2 on a length L/2 and -Q/2 on the remaining length L/2. R * P (e) Show that the results with this new distribution, in the L << R limit is consistent with a dipole that has dipole moment p=(Q/2)(L/2) = QL/4 and is oriented tangent to the arc (perpendicular to R). You will want to use the correct small angle approximation for cosine (see the exercises!)
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Transcribed Image Text:(b) Find the field at a test point placed at the center of the circle that the arc is part of. Again, follow the process, and remember that the sample charge dq occupies a small length of the rod, and that length is now a small part of an arc. (c) Check that your results for the case L << R give you the field of a point source with charge Q, a distance R away. You will want to use the small angle approximation from the exercises: sin 0 z 0 for 0 << 1 (d) With minimal reanalysis (just note where you need to change the work you did above and how that changes the result) find the field at the test point if we replace the charge on half the rod with the opposite charge, so we have +Q/2 on a length L/2 and -Q/2 on the remaining length L/2. R * P (e) Show that the results with this new distribution, in the L << R limit is consistent with a dipole that has dipole moment p=(Q/2)(L/2) = QL/4 and is oriented tangent to the arc (perpendicular to R). You will want to use the correct small angle approximation for cosine (see the exercises!)
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