A uniform electric field has magnitude E and is directed in the negative x direction. The potential difference between point a (at x=0.50 m ) and point b (at x=0.85 mm ) is 290 V . a) Calculate the value of E. b) A negative point charge q=−0.200μC is moved from b to a. Calculate the work done on the point charge by the electric field.

Oppositely charged parallel plates are separated by 6.30 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? N/C (b) What is the magnitude of the force on an electron between the plates? N (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.80 mm from the positive plate?

The potential in a region of space due to a charge distribution is given by the expression V = ax?z + bxy - cz? where a = -4.00 V/m3, b = 7.00 V/m2, and c = 4.00 V/m2. what is the electric field vector at the point (0, -9.00, -8.00) m? Express your answer in vector form. E = 63i + 64k Note that the potential is a function of three variables. Review rules for partial differentiation. V/m

Oppositely charged parallel plates are separated by 5.10 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? N/C (b) What is the magnitude of the force on an electron between the plates? N (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.92 mm from the positive plate?

A positive charge is evenly distributed on the surface of a metal sphere centered at the origin of the coordinate system. The positive charge produces an electric field that points outwardly in the radial direction. A positive test charge is fixed at a distance R₁ from the center of the coordinate system, far from the surface of the sphere. The electric potential at R₁ is 10V. The positive test charge is then allowed to move freely until it reaches a distance R₂=2R₁ from the center of the coordinate system. What is the electric potential (in Volts) of the test charge at its new resting point? 10

In a certain region of space, the electric potential varies along an x-axis as shown in the figure below. The scale of the vertical axis is set by V, = 8000 V. Find the x-component of the electric field in the interval de. V i - m -5 b Save for Later V₂ 0 d g 5 x (m) Submit Answer

Problem 2: A point mass of charge q > 0 moves at 35° to a uniform electric field E for a total distance d. Part (a) Select a diagram that follows from the problem description. Part (b) The charge q travels from point y, to point y2, where the total traveled distance is d. Find the potential difference that the charge traverses. When you enter your answer you can assume that y, = 0 V2 - V = cos(a) cos(o) cos(e) 7 8 9 HOME sin(a) sin(@) sin(e) 5 6 3 d E - END h Vol BACKSPACE DEL CLEAR

B A A 6 µC point charge is placed at the origin as shown in the figure above, where a = 2 cm, 6 = 2.4 cm, c = 1 cm, and d = 2.7 cm. Find the potential at the points A, B and C: VA V VB = V Vc = V

The plates of a parallel-plate capacitor have a separation of 3.52 mmmm , and each has an area of 15.0 cm2cm2 . Each plate carries a charge of magnitude 3.85×10−8 CC . The plates are in vacuum. a) what is the capacitance? b)What is the potential difference between the plates? c)What is the magnitude of the electric field between the plates?

The electric potential at points in an xy plane is given by V= (1.70 V/m²)x² -(3.00 V/m²)y2. What are (a) the magnitude of the electric field at the point (2.90 m, 1.60 m) and (b) the angle that the field there makes with the positive x direction. (a) Number i (b) Number i Units Units