A uniform 15 kg pipe of length 5.0 m has a N force applied 4.0 m from its lower end as shown. positive and FT 160 N T₁ 27. 5₁d.-

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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HELP! I am confused with this, so can you please provide an explanation on what this means and show the answer by plugging in the numbers while solving (also confused about choosing which one to be point of rotation) It would help a lot! Thank you!
end as shown.
T
18. A uniform 15 kg pipe of length 5.0 m has a 180 N force applied 4.0 m from its lower
Let c = positive and
Fr 160 N
Cc = negative
Tc = čcc
d₁ = 2.5m
ET = Te-Tu
de=4.0m
34°
42°
5
Τι
1.0 m
=
Er. 5₁d. - T₁dz
mg cos 34. d₁ - Tros 48'd
= -123 Nm
123 Nm counter-
clockwise
Transcribed Image Text:end as shown. T 18. A uniform 15 kg pipe of length 5.0 m has a 180 N force applied 4.0 m from its lower Let c = positive and Fr 160 N Cc = negative Tc = čcc d₁ = 2.5m ET = Te-Tu de=4.0m 34° 42° 5 Τι 1.0 m = Er. 5₁d. - T₁dz mg cos 34. d₁ - Tros 48'd = -123 Nm 123 Nm counter- clockwise
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