A U.S. Food Survey showed that Americans routinely eat beef in their diet. Suppose that in a study of 49 consumers in Illinois and 64 consumers in Texas the following results were obtained from two samples regarding average yearly beef consumption:               Illinois                                     Texas              = 49                                     = 64                                                 = 54.1lb                              = 60.4lb             S1 = 7.0                                    S2 = 8.0  Develop a 95% confidence Interval Estimate for the difference between the two population means.

Two groups of individuals were compared with respect to a high carbohydrate low- fat diet (LF) and a high-fat low carbohydrate diet (LC). Mood was assessed using a total mood disturbance score where a lower score is associated with a less negative mood. Assuming that the random samples come from independent normal distributions with a common but unknown variance, construct a 95% confidence interval for the difference between the two population means, LC less LF. Group LC LF n 12 13 mean 47.3 19.3 standard deviation 28.3 25.8

A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken a statistical methods course that involved significant computer interaction. Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 12 nursing students from Group 1 resulted in a mean score of 54.7 with a standard deviation of 6. A random sample of 15 nursing students from Group 2 resulted in a mean score of 66.6 with a standard deviation of 3. Can you conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2? Let μ represent the mean score for Group 1 and μ₂ represent the mean score for Group 2. Use a significance level of a = 0.1 for the test. Assume that the population variances are equal and that the two populations are normally distributed. Step 3 of 4: Determine the decision rule for…

Suppose that Sandy is an analyst for the bicyling industry and wants to estimate the asking price of used entry-level road bikes advertised online in the southeastern part of the United States. She obtains a random sample of n = 10 online advertisements of entry-level road bikes. She determines that the mean price for these 10 bikes is $659.87 and that the sample standard deviation is s = $197.02. She uses this information to construct a 95% confidence interval for u, the mean price of a used road bike. What is the upper limit of this confidence interval? Please give your answer to the nearest cent.