A typical ten-pound car wheel has a moment of inertia of about 0.35 kg · m². The wheel rotates about the axle at a constant angular speed making 35.0 full revolutions in a time interval of 5.00 s.

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A: Given that                The angular displacement (θ) = 5.85radians               Torque…

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A: Given : τ = 170 N.m W = 4715 J Ki = 1320 J

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A: Given: M→=-3i^+6j^-5k^N→=-2i^+3j^+k^

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A: The torque is given as, τ=τosinθθ1=0o=0 radθ2=110o=1.92 rad

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A: Given, moment of inertia =0.038 kg.m2time period T =5.0 secwe have to calculate the kinetic energy.

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A: change in kinetic energy= work done by friction12mv2-12mu2=work done by frictionhere m=mass of toy=…

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A: Given A̅ = -3î + 6ĵ -5k̂  B̅ = -2î + 3ĵ +k̂

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A: Given data:  A→ = 5i^ - 6j^ + 2k^B→ = 3i^ - 5k^ Required: The dot product of vector A and vector B

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