A triangular shaped channel having a slope of 0.0001with a depth of 1.215 m..It is made of timber with n=0.012.Calculate the discharge of the channel using the best hydraulic or the most economical triangular section Select one: O a. 0.4371 cu m/s O b. 0.6982 cu m/s O c. 0.5892 cu m/s d. 0.6434 cu m/s O e. 0.3092 cu m/s

A triangular shaped channel having a slope of 0.0001with a depth of 1.215 m..It is made of timber with n=0.012.Calculate the discharge of the channel using the best hydraulic or the most economical triangular section Select one: O a. 0.4371 cu m/s O b. 0.6982 cu m/s O c. 0.5892 cu m/s d. 0.6434 cu m/s O e. 0.3092 cu m/s

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

In a circular channel 2.5meters in diameter, flowing below half full, the water surface width is 2.415meter in length. a.Compute the hydraulic radius. b.The channel is laid on a grade of 24.146meters per mile; compute its discharge using Manning’s formula withn= 0.025. c.For flow as in (b), compute the C value in the Chezy formula. d.Using C in (c), and for flow as in (b), compute the value of Kutter’s nin the Kutter’s C formula. Simplify your solution, no solution by calculator or shift solve. e.Compute the maximum velocity that may occur for the given circular channel using as in (d) and Manning’s formula.
The surface of an open channel lined with brass has a bed slope of 1:1000 and a Manning's coefficient of 0.011. Water is transported at a rate of 10 m/s in uniform flow. Determine the best hydraulic section for the following geometric shapes. (b) (i) A semicircular open channel. (ii) A parabolie open channel.
2. Four reservoirs connection is shown below. Determine the discharges in each pipe using Manning's Equation withn = 0.012. Draw the final hydraulic gradient line (HGL). Pipe AX Length of pipe (m) 1500 Diameter of pipe (m) 0.30 0.25 BX 800 XY 400 0.30 500 1600 CY 0.20 DY 0.20 WS ELEV. = 300 m WS ELEV. = 150 m WS ELEV. = 100 m ELEV. = 75 m WS
Q1:- Determine the cross section and discharge of the stable hydraulic section of a channel excavated in a noncohesive material having ro 0.1 lb/ft, S e = 31°, and n 0.020. 0.0004,
(Problem 10.51) Water flows from a storage tank, over two triangular weirs, and into two irrigation channels. The head for each weir is 0.4ft and the flowrate in the channel fed by the 90-degree V-notch weir is to be twice the flowrate in the other channel. Determine the angle O for the second weir. .. (Ans: 2 = 53-degrees)
A circular section channel 3m in diameter has a depth of flow of 1.0m and is laid to a gradient of 1:1000, and n = 0.012. a) compute the hydraulic radius of the channel. Blank 1 b) compute the rate of flow in the channel in m³/s. Blank 2 Blank 1 Add your answer Blank 2 Add your answer
2 Determine the vertex angle of the V hotch weir cut at one end of a tank having a square section ol 10m x 10m with an initialhead of 1.20m i dischärges 100 m ol water in 377 seconds. Use correction factor C 0 60.
Q. The hydraulic radius (m) for a circular pipe of diameter (D) behaving as open channel is given by ?
Q/shows a hycreaulic structur thut was built on opm channel . The residunl head at point f calculated by using Lon's theory is equal to 1.25m. Thi suk o + and G2.5. bydraulic gradient is equal to : 50 Lon's VIs WIL h, = 125 - +4, G.2.5 12465 15m 12m 15m
CORRECT LETTER PLS 1. Which of the following least affects hydraulic gradient or slope of HGL? A. PIPE LENGTHB. PIPE DIAMETERC. TYPE OF PIPED. FLOE RATE 2. In laminar flow, which is correct?BJ: higher Re value has higher friction factorJB: lower Re value has lower friction factorGroup of answer choices A. BJ is false and JB is true B. BJ is false and JB is false C. BJ is true and JB is false D. BJ is true and JB is true 3. In a system with 4 reservoirs and 2 pipe junctions, how many continuity equations are formulate? A. 3B. 2C. 1D. 4E. 5
Question 4 A nearly horizontal rectangular section with a width of 25 feet carries 1500 cfs. There is a contraction in the channel of 10 feet. If the depth at the contraction is critical determine the upstream channel depth in feet. Do not include the units in the solution and round to the tenths digit. D Question 5 Assume you have the channel reach shown that is mild (dn>dc); calculate the upstream and downstream depths of the hydraulic jump (note there is a hydraulic jump because upstream there is a gate controlling the water to below critical. Also determine the length of the hydraulic jump. The flow rate in the channel is 1500 cfs, , the base width is 25 ft and the normal depth is 10 feet. upstream depth - ft downstream depth = ft length of jump = ft Round all you answers to the hundredths digit and do not include units in the solutions and on your scratch paper provide a sketch of the channel in profile view. please answer both, will upvote
How much is stress at point.... in the following culvert considering applied moment of 100 kips-in.(HINT: you need to use a = MI/I) 0.5 in. 0.5 in. -9 in. 100 kips-in 0.5 in. 6 in.