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A torus is formed by revolving the region bounded by the circle x² + y² = 1 about the line x = 2 (see figure below). -1 - 1 y Volume = cubic units. 1 2 X Find the volume of this "doughnut-shaped" solid. (Hint: The integral √1 - 2² da represents the area of a semicircle. So you can find this specific integral without using antiderivative.)

A torus is formed by revolving the region bounded by the circle x² + y² = 1 about the line x = 2 (see figure below). -1 - 1 y Volume = cubic units. 1 2 X Find the volume of this "doughnut-shaped" solid. (Hint: The integral √1 - 2² da represents the area of a semicircle. So you can find this specific integral without using antiderivative.)

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter10: Measurement, Area, And Volume
Section10.8: Volumes Of Pyramids And Cones
Problem 13E
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A torus is formed by revolving the region bounded by the circle x² + y² = 1 about the line * = 2 (see figure below). -1 -1 y 1 2 I X Find the volume of this "doughnut-shaped" solid. (Hint: The integral √1 - 2² da represents the area of a semicircle. So you can find this specific integral without using antiderivative.) Volume = cubic units.
Transcribed Image Text:A torus is formed by revolving the region bounded by the circle x² + y² = 1 about the line * = 2 (see figure below). -1 -1 y 1 2 I X Find the volume of this "doughnut-shaped" solid. (Hint: The integral √1 - 2² da represents the area of a semicircle. So you can find this specific integral without using antiderivative.) Volume = cubic units.
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