A three-dimensional array called watermelon is declared as based on the row-wise manner as below: int watermelon [3][2][2]= {9, 7, 1, 5, 9, 7, 1, 5, 9, 7 ,1, 5}; Rewrite the sequence of watermelon array if it is accessed in
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A three-dimensional array called watermelon is declared as based on the
row-wise manner as below:
int watermelon [3][2][2]= {9, 7, 1, 5, 9, 7, 1, 5, 9, 7 ,1, 5};
Rewrite the sequence of watermelon array if it is accessed in column wise manner.
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- (Electrical eng.) Write a program that declares three one-dimensional arrays named volts, current, and resistance. Each array should be declared in main() and be capable of holding 10 double-precision numbers. The numbers to store in current are 10.62, 14.89, 13.21, 16.55, 18.62, 9.47, 6.58, 18.32, 12.15, and 3.98. The numbers to store in resistance are 4, 8.5, 6, 7.35, 9, 15.3, 3, 5.4, 2.9, and 4.8. Your program should pass these three arrays to a function named calc_volts(), which should calculate elements in the volts array as the product of the corresponding elements in the current and resistance arrays (for example ,volts[1]=current[1]resistance[1]). After calc_volts() has passed values to the volts array, the values in the array should be displayed from inside main().IN C# Q. Lucky Number Definition:● A lucky number is a number whose value is equal to the occurrence of that number in anarray.○ [2, 2, 3, 3] => 2● If there is more than one number whose value is equal to the occurrence of that numberin an array, then the lucky number will be the one with the maximum value among alllucky numbers.○ [1, 2, 2, 3, 3, 3, 4] => 3● If there is no number in an array whose value is equal to the occurrence of that numberin the array then the lucky number will be -1.○ [5] => -1Implement a function getLuckyNumber(numbers) that takes an array of positive integers asinput and returns the lucky number from the array.Test Cases:● getLuckyNumber([2, 2, 3, 3]) => 2● getLuckyNumber([1, 2, 2, 3, 3, 3, 4]) => 3● getLuckyNumber([5]) => -1getLuckyNumber(numbers){// function implementation// return number whose value is equal to the occurrence of the number in the array// e.g [2, 2, 3, 3] => lucky number = 2// in case there are multiple lucky numbers…Kotlin Programming Array Exercise Create a Kotlin program that can print a specified element in an array given the code below: fun main(){ val pets=arrayOf("dog","cat","bird") for(element in pets){ println(element + " ") } } Thanks for answer I need it now how do we print the 2nd element?
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- Lab Goal : The lab was designed to teach you how to use arrays to simplify solving more complex problems. Lab Description : Given a provided array, determine how many groups of a specified size exist.For the array [1,1,1,2,2,2,3,3,3,4,5,6,7] , there are 7 groups with at least one, 3 groups with at least 2, and 3 groups with at least 3. A group is a series of same values. 1 1 1 is a group of 3, but it also is a group of 1 and 2. To count as a group, all values must be the same. 1 1 1 is a group of 3 because there are 3 1s in a row.Lab Goal : The lab was designed to teach you how to use arrays to simplify solving more complex problems. Lab Description : Given a provided array, determine how many groups of a specified size exist.For the array [1,1,1,2,2,2,3,3,3,4,5,6,7] , there are 7 groups with at least one, 3 groups with at least 2, and 3 groups with at least 3. A group is a series of same values. 1 1 1 is a group of 3, but it also is a group of 1 and 2. To count as a group, all values must be the same. 1 1 1 is a group of 3 because there are 3 1s in a row.Sample Data : 3 3 3 3 3 9 4 4 4 5 5 5 5 6 6 7 7 7 8 8 8 8 8 8 8 8 1 2 3 4 5 6 7 8 9 1 1 1 2 1 1 3 3 3 3 3 3 3 3 3 3 4 4 4 5 4 4 4 6 Sample Output : [3, 3, 3, 3, 3, 9, 4, 4, 4, 5, 5, 5, 5, 6, 6, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8]size 1 count == 7size 2 count == 6size 3 count == 5size 4 count == 3size 5 count == 2size 6 count == 1 [1, 2, 3, 4, 5, 6, 7, 8, 9]size 1 count == 9size 2 count == 0size 3 count == 0size 4 count == 0 [1, 1, 1, 2, 1, 1, 3, 3, 3, 3, 3, 3, 3,…Lab Goal : The lab was designed to teach you how to use arrays to simplify solving more complex problems. Lab Description : Given a provided array, determine how many groups of a specified size exist.For the array [1,1,1,2,2,2,3,3,3,4,5,6,7] , there are 7 groups with at least one, 3 groups with at least 2, and 3 groups with at least 3. A group is a series of same values. 1 1 1 is a group of 3, but it also is a group of 1 and 2. To count as a group, all values must be the same. 1 1 1 is a group of 3 because there are 3 1s in a row.Sample Data : 3 3 3 3 3 9 4 4 4 5 5 5 5 6 6 7 7 7 8 8 8 8 8 8 8 81 2 3 4 5 6 7 8 91 1 1 2 1 1 3 3 3 3 3 3 3 3 3 3 4 4 4 5 4 4 4 6Sample Output : [3, 3, 3, 3, 3, 9, 4, 4, 4, 5, 5, 5, 5, 6, 6, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8]size 1 count == 7size 2 count == 6size 3 count == 5size 4 count == 3size 5 count == 2size 6 count == 1[1, 2, 3, 4, 5, 6, 7, 8, 9]size 1 count == 9size 2 count == 0size 3 count == 0size 4 count == 0[1, 1, 1, 2, 1, 1, 3, 3, 3, 3, 3, 3, 3, 3,…
- 2. Intersection Write a method/function that takes two circular arrays, their sizes and start indexes and returns a linear array containing the common elements between the two circular arrays. DO NOT convert the circular arrays to linear arrays to solve the problem. Input: Circular array 1: [40,50,0,0,0,10,20,30] (start_1 =5, size_1 =5) Circular array 2 : [10,20,5,0,0,0,0,0,5,40,15,25] (start_2=8, size_2 =7) Output: [10,20,40] Use Python LanguagePrint the elements of the array ‘a’ using the mentioned notations: int a[]={1,2,3,4,5}; int *p; p = a; for (int i = 0; i< 5; i++) { //Subscript notation with name of array //Subscript notation with pointer 'p' //Offset notation using array name //Offset notation using pointer 'p' }2 #include 3 #include 4 5 6 7 8 void printArray(int myArr[][ARRAY_COLS]) 9- { 10 11- 12 13- const int ARRAY_COLS = 10; 3; const int ARRAY_ROWS 14 15 16 17 18 } 19 20- /* 21 26 27 } 37 } 38 44 45 46 47 48 49 50 for (int i = 0; i < ARRAY_ROWS; i++) { 22 23 */ 24 void zeroCorners (int myArr[] [ARRAY_COLS]) 25 - { myArr[0][0] = 999; 51 52 } This function currently sets the upper-left-hand corder of the 2D array to 999 Instead, this should set all 4 corners of the 2-D array to zero. for (int j = 0; j < ARRAY_COLS; j++) { std::cout << myArr[i][j] << ", "; } 28 29 - /* 30 This function should Loop through every element in the 2-D array. If an element is odd, then subtract one from to make it even. 31 32 HINT: function printArray() is an example of Looping through every element in 2D array */ 33 34 void makeEven (int myArr[][ARRAY_COLS]) 35 - { 36 // TODO - put code here std::cout << "\n"; 53 54 } 55 39 int main() 40 - { 41 - 42 43 int arr[][ARRAY_COLS] { {1, 2, 3, 4, 5, 6, 7, 8, 9, 10),…