A thin rod initially lies at rest along the x axis with one end at x = -1.7 m and the other end at x = 2.3 m. The rod has anonuniform density given (in kg/m) by the function A (x) = 0.6x4 + 3.6x?. At t 0, a force of 27.0 N is applied to the entirerod in the -x direction. What is the position of the center of mass of the rod at t = 3.4 s?X cm =m

Density function,λ(x)=0.6x4+3.6x2Now,Mass of rod,m=∫-1.72.3dmm=∫-1.72.3λ(x).dxwhere,dx is length of…

A thin rod initially lies at rest along the x axis with one end at x = -1.7 m and the other end at x = 2.3 m. The rod has a nonuniform density given (in kg/m) by the function A (x) = 0.6x + 3.6x. At t = 0, a force of 27.0 N is applied to the entire rod in the -x direction. What is the position of the center of mass of the rod at t = 3.4 s? Xcm =

A thin rod initially lies at rest along the x axis with one end at x = -1.7 m and the other end at x = 2.3 m. The rod has a nonuniform density given (in kg/m) by the function A (x) = 0.6x + 3.6x. At t = 0, a force of 27.0 N is applied to the entire rod in the -x direction. What is the position of the center of mass of the rod at t = 3.4 s? Xcm =

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

What is the norminal force, N in kilo Newtons(kN). What is the shear force, V in kilo Newtons (kN). Find the bending moment, M in kilo Newton metres (kNm).
8
I need the answer as soon as possible
With direction and angles specified, please
Three identical 8.60-kg masses are hung by three identical springs, as shown in the figure. (Figure 1) Each spring has a force constant of 5.90 kN/m and was 11.0 cm long before any masses were attached to it. Make a free-body diagram for the top mass. Draw the vectors starting at the black dot at the center of the top mass.
Compare the magnitudes of the equilibrant vectors measured from the experiment with those obtained from the graphical and component methods. Example: A: 200 g 60° above +x axis B: 300 g 45° above -x axis C: 400 g 30°below -x-axis A, A cos a = 1.96 N x cos 60° = 0.98 N B₂B cos b = 2.94 N x cos 135º = -2.08 N C, C cos g = 3.92 N x cos 210°= -3.39 N R₂-A, + B + C₂ = -4.49 N A, A sin a = 1.96 N x sin 60° = 1.70 N By B sin b = 2.94 N x sin 135º = 2.08 N C, C sin g = 3.92 N x sin 210° = -1.96 N Ry= Ay+ By + Cy = 1.82 N Questions: I: (a) A: 200 g along +x axis B: 100 g 45° above -x axis A₂ = A cos a = B₂ =B cos b = R₂-A₂+ B₁₂= A₂ = A sin a = B, = B sin b = R₂ = A + B₂ = R=(R₂. R₂):_ Quadrant R = √ (R₂²+R₂²) = Direction:q=tan [R, /R.] (c) A: 100 g along -y axis B: 200 g along -x axis A = A cos a = B = B cos b = R₂-A₂+ B₂ = A = A sin a = B, B sin b = R=A, +B₂ = R=(R₁, R₂): Quadrant R = √ (R₂²+R₂²) = Direction:q tan¹ [R, /R]
The force P of magnitude 50 kN is acting at 215° from the x-axis. Find the components of P in v 157° from x, and u negative 69° .from x Pv367.44 kN & Pu358.95 kN O Pv=58.95 kN & Pu=67.44 kN O
45 l a O O 11:rE STATIC MONTHL... Find the resultant force of the following? 2 m F = 600 N 3.5 m 0.5 m E- 450 N Ai 1.5 m 1.5 m 0.5 m y
Calculate the total moment of the system about point A, when P1 = 10 .kN, P2 = 5 kN and 0 = 30° %3D %3D P, 25 kN.m 1.5 m A -1.5 m 1.5 m- P2 اخترأحد الخيارات a. 29.00 kN.m (CW) b. 29.55 kN.m (CCW) c. 4.75 kN.m (CCW) d. 4.00 kN.m (CW)
Draw force diagram and answer a and b. Show complete solutions.