(a) The pdf of the k x 1 random vector X isSx (x) = II :a,I (n)exp -Ea,'x,0 < x < 00i=1i=1(i) Determine the mgf of X : 3 x 1.(ii) The mgf of X : p x 1I is Mx (t) = [1 (1 – 4 )akUse differentiation to find the variance of X.

In this problem, we are given the probability density function (pdf) of a k-dimensional random…

(a) The pdf of the k x 1 random vector X is √x 6) = [² fx 1=1 -n I (n.) |exp(-2₁7¹x,). (i) Determine the mgf of X: 3 x 1. (ii) The mgf of X : p x 1 is Mx (t) = 1 (¹-4) k=1 ak Use differentiation to find the variance of X. -nk 0< 0

(a) The pdf of the k x 1 random vector X is √x 6) = [² fx 1=1 -n I (n.) |exp(-2₁7¹x,). (i) Determine the mgf of X: 3 x 1. (ii) The mgf of X : p x 1 is Mx (t) = 1 (¹-4) k=1 ak Use differentiation to find the variance of X. -nk 0< 0

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter2: Exponential, Logarithmic, And Trigonometric Functions

Section2.CR: Chapter 2 Review

Problem 111CR: Respiratory Rate Researchers have found that the 95 th percentile the value at which 95% of the data...

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Question

(a) The pdf of the k x 1 random vector X is
Sx (x) = II :
a,
I (n)
exp -Ea,'x,
0 < x < 00
i=1
i=1
(i) Determine the mgf of X : 3 x 1.
(ii) The mgf of X : p x 1I is Mx (t) = [1 (1 – 4 )
ak
Use differentiation to find the variance of X.

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