a) The number of students who come into the tutoring center between 8 and 8:30am has a Poisson distribution with λ =5. Determine P(x ≤ 2) b) How many students can the tutoring center be 95% confident that the number of students on any given day will not exceed that number?
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Poisson distribution :
λ = 5
Probability :
P(X=x) = (λx * e(-λ)) / x!
Here :
x! = (x*(x-1)*(x-2)*.........1)
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- Emilio, the owner of Pepe Delgados, is interested in taking a more statistical approach topredicting customer load. He begins the process by gathering data on the number of arrivals infive-minute intervals. The data below represent the arrivals in five-intervals between 7:00p and8:00p every Saturday for three weeks. Assume that arrivals are Poisson distributed. Thequestions that follow pertain to the 7:00p to 8:00p time period.*Image Attached*a. Compute lambda using the data from all three weeks as one data set.b. What is the probability that no customers arrive during any five-minute interval?c. What is the probability that six or more customers arrive during any five-minuteinterval?d. What is the probability that during a 10-minute interval fewer than four customersarrive? e. What is the probability that no customers arrive during any 10-minute interval?Compare with part b.f. What is the probability that exactly eight customers arrive in any 15-minute interval?A load of 200 desk lamps has just arrived at the warehouse of Lighting, Inc. Random samples of n = 5 lamps are checked. If more than one lamp is defective, the whole lot is rejected. Set up the OC curve for this plan and develop the AOQ curve.A hot dog concession at Safeco Field sells an average of 54.67 hot dogs per hour (believed to follow a Poisson Distribution). How many hot dogs should the vendor stock in order to be 93% sure it has enough hot dogs for 1.5 hour(s)? F−1(0.93)=
- The ground-up losses have an exponential distribution with mean 750,000. A deductible of 500,000 is applied to the product and the frequency distribution for the total number of losses, , is Poisson with mean 2. What is the percentage of policyholders be expected to have at least one claim paid to them?We have a Poisson distribution for cacti with a mean of 280 per square kilometer. They are asking for the mean of cacti per 10,000 square meters. They are telling us that 1 square kilometer = 1,000,000 square meters. My confusion is on converting the units. When they say 280 per square kilometer, are they saying 280 divided by square kilometer? I've attached an image of my work. My professor said that the answer is 2.8.Suppose that X follows a poisson distribution with parameter λ=1.416 . P(X≥0)≅?
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