(a) The elevator accelerates upward from rest at a rate of 1.7 for 1.6 s. s2 (i) Newton's Second Law in the y-direction can be written as T= 1 EF,=-1 meg+ 1 •m¸a (ii) Calculate the tension in the cable supporting the elevator. T= 19567 XN (iii) How high has the elevator moved during this time? Ay= (iv) Calculate the velocity of the elevator after this time. m v(t=1.6 s) = %3D S

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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An elevator shown below filled with passengers has a mass of 1800 kg. The elevator does motions (a) through (c) in succession.

 

(a) The elevator accelerates upward from rest at a rate of 1.7
for 1.6 s.
s2
(i) Newton's Second Law in the y-direction can be written as
T= 1
EF,=-1
meg+ 1
•m¸a
(ii) Calculate the tension in the cable supporting the elevator.
T= 19567
XN
(iii) How high has the elevator moved during this time?
Ay=
(iv) Calculate the velocity of the elevator after this time.
m
v(t=1.6 s) =
%3D
S
Transcribed Image Text:(a) The elevator accelerates upward from rest at a rate of 1.7 for 1.6 s. s2 (i) Newton's Second Law in the y-direction can be written as T= 1 EF,=-1 meg+ 1 •m¸a (ii) Calculate the tension in the cable supporting the elevator. T= 19567 XN (iii) How high has the elevator moved during this time? Ay= (iv) Calculate the velocity of the elevator after this time. m v(t=1.6 s) = %3D S
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