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A test charge of +2μC is placed halfway between a charge of +6μC and another of +4μC separated by distance 2d = 13 cm.
The free body diagram of q2 from Part 1 should look like this:
The force on q2 due to q1 is repulsive and acts to the right. The force on q2 due to q3 is repulsive and acts to the left. ?3→2>?1→2?3→2>?1→2
because q3>q1.
(a) Calculate the force on the test charge by the +6μC charge. |
Transcribed Image Text:A test charge of +2µC is placed halfway between a charge of +6μC and another of +4µC separated by
distance 2d = 13 cm.
+4uC
9₁ = +4 µC
d
The free body diagram of q₂ from Part 1 should look like this:
+2μC
F3-2
✔N
d
q2 = +2 μC
F₁-2
+6μС
X
The force on q2 due to q₁ is repulsive and acts to the right. The force on q2 due to q3 is repulsive and
acts to the left.
F3-2 > F12 F3→2 > F1→2
q3 = +6 μC
because 9391.
(a) Calculate the force on the test charge by the +6µC charge.
Hint: The force in the positive x-direction is positive and the negative x direction is negative.
N
(b) Calculate the force on the test charge by the +4µC charge.
N
(c) Calculate the net force on the test charge by both the charges.
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