A temperature controller, designed to work in a steam envi- ronment, involves a bimetallic strip constructed of brass and steel, connected at their ends by rivets. Each of the metals is 2.0 mm thick. At 20°C, the strip is 10.0 cm long and straight. ur model, due to the Find the radius of curvaturer of the ---10:00 assembly at 100°C. See Fig. 17-22.

96 Figure 18-59 shows a composite bar of length L = L1 + L2 and con- sisting of two materials. One mate- rial has length L, and coeffi- cient of linear expansion a;; the other has length L2 and coefficient of linear expan- sion ar. (a) What is the coeffi- cient of linear expansion a for the composite bar? For a particular composite bar, L is 52.4 cm, material 1 is steel, and material 2 is brass. If a = 1.3 x 10-5/C", what are the lengths (b) L1 and (c) L2? Figure 18-58 Problem 95. Le Figure 18-59 Problem 96.

The principal virtue of Pyrex glass is that its coefficient oflinear expansion is much smaller than that for ordinaryglass (Table 13–1). Explain why this gives rise to the higherheat resistance of Pyrex

One assistant poured 998.00 cm3 of liquid mercury into a 1000.00-cm3 -flask, when both the mercury and the glass were at 4.0 ◦C. The teacher, has asked you to determine the maximum temperature he can heat the system to (to the thousandth of a degree Celsius) before the mercury overflows if mercury has a coefficient of volume expansion of 18.0 * 10-5 ◦C-1 and the glass of the flask has a coefficient of volume expansion of 1.8 * 10-5 ◦C−1.

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SUBJECT: THERMODYNAMIC COURSE: II ASSI.LACTURE: NATIQ ABBAS Еxample 2:- Refrigerant-134a enters the compressor of a refrigerator as superheated vapor at 0.14 MPa and -10°C at a rate of 0.05 kg/s and leaves at 0.8 MPa and 50°C. The refrigerant is cooled in the condenser to 26°C and 0.72 MPa and is throttled to 0.15 MPa. Disregarding any heat trans fer and pressure drops in the connecting lines between the components; determine (a) the rate of heat removal from the refrigerated space and the power input to the compressor, and (b) the coefficient of performance of the refrigerator. Solution: - P 0.14 MPa T = -10 C d h=246.36 kJ/kg OF SAMARRA P 0.8 MPa h2 = 286.69 kJ/kg O P 0.72 MPa T- 26 C - hg = 87.83 kJ/kg h3 =h, = 87.83 KJ/kg h4 = h3 (throttling) h4 = 87.83 kJ/kg 0.8 MPa 50°C 0.72 MPa/ 26 C 0.15 MPa 0.14 MPa -10°C SUBIECT: THERMODYNAMIC COURSE: II ASSI.LACTURE: NATIO ABBAS RING

Ur an exposed wheel diameter of 30.000 cm at a temperature of 15 C and the internal diameter of the iron rim of 29.930 cm. So to what temperature must the rim be heated in order for it to slide on the wheel? For this type of iron ('a = 1.10x10 c) %3D