College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A telephoto lens—designed to produce large images of distant objects—sticks out quite far from the front of the camera. Explain why this is so.
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- Spherical aberration is due to light rays O a. passing through the outer portions of a lens not focusing at the same point as rays that pass through the center O b. of different wavelength not focusing at the same point O C. passing through the lens in the vertical direction not focusing at the same point as rays passing through the lens in the horizontal direction O d. passing through the outer portions of a lens being absorbed more than rays that pass through the centerarrow_forwardIf the screen is at the right position and the object is in a right position, the lens will focus the image of the object onto the screen. If the screen is anywhere else, the object will look blurry or won't be seen. The optical table has a meter-tape attached to the side, to give the position of the items. If the object is in a wrong position, the lens will defocus the light -- spread it out. That means that the screen can't be placed anywhere to display a focused image. If xL = 32.7 cm and the focal length is f = 20.8 cm, give a position (xO) that results in the light from the object spreading out. (There are infinitely many such positions.)arrow_forward2. Show that the minimum distance between a real object and its real image given by a convergent lens of focal length f is 4f. Get q as a function of p from 1/p + 1/q = 1/f. Take the derivative of s = p +q to find the value of p for which s is minimum.arrow_forward
- st 8. A converging lens (f₁ = 12.0 cm) is located 27.3 cm to the left of a diverging lens (f₂ placed 32.4 cm to the left of the converging lens. Find the overall magnification. ssf60*³ f60 ssf ssf60 ssi f6 -6.6 cm). A postage stamp is sf60 ssf60 50 sstarrow_forwardA clerk at the local grocery store wears glasses that make her eyes look smaller than they actually are. Is the clerk nearsighted or farsighted? Explain.arrow_forwardTwo lab partners, Mary and Paul are both farsighted. Mary has a near point of 67.8 cm from her eyes and Paul has a near point of 130 cm from his eyes. Both students wear glasses that correct their vision to a normal near point of 25.0 cm from their eyes, and both wear glasses 1.80 cm from their eyes. In the process of wrapping up their lab work and leaving for their next class, they get their glasses exchanged (Mary leaves with Paul's glasses and Paul leaves with Mary's glasses). When they get to their next class, find the following. (a) Determine the closest object that Mary can see clearly (relative to her eyes) while wearing Paul's glasses.Try splitting the problem into two steps. First, find the refractive power of each pair of glasses and then the closest object that each student can clearly view while wearing the other student's glasses. Think carefully about whether a particular object or image distance should be relative to the glasses or relative to the eyes. Give careful…arrow_forward
- Create a ray diagram for eyeglasses that contain a diverging lens. Assume you are looking at a 2 cm tall object that is 4 cm from the lens. The focal length is 3 cm. What type of vision are they used to correct? Give both names. How do they do this? Explain.arrow_forwardA clerk at the local grocery store wears glasses that make her eyes look larger than they actually are. Is the clerk nearsighted or farsighted? Explain.arrow_forward1. A patient enters an eye doctor’s office and finds the doctor tells him that his near point is 10.0 cm. The doctor also finds the patient’s far point (with eyes relaxed) is 125 cm. Each eye lens can be assumed to be 2.00 cm from the retina. a) Between what limits (units: diopters) does the power of this patient’s lens (technically lens+cornea combination) vary? b) The doctor is going to prescribe glasses. Calculate the power of the eyeglass lens the patient should use for relaxed distance vision. Is the lens converging or diverging?arrow_forward
- You need to use a 23- cm -focal-length lens to produce an inverted image one third the height of an object. At what distance from the object should the lens be placed? Express your answer with the appropriate units.arrow_forwardYou are a marine biologist and want to pull a star fish out of a tank of water for testing. Looking from the top of the tank, where is the actual starfish compared to the image of the starfish that you see from the surface? Explain.arrow_forward
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