A tank contains 100 kg of salt and 2000 L of water. A solution of a concentration 0.025 kg of salt per liter enters a tank at the rate 7 L/min. The solution is mixed and drains from the tank at the same rate. a.) What is the concentration of our solution in the tank initially? (kg/L) concentration = 100/2000 b.) Find the amount of salt in the tank after 5 hours. (kg) amount = e^(-7*5*60/2000)*2000 c.) Find the concentration of salt in the solution in the tank as time approaches infinity. concentration 0.025 (kg/L)
A tank contains 100 kg of salt and 2000 L of water. A solution of a concentration 0.025 kg of salt per liter enters a tank at the rate 7 L/min. The solution is mixed and drains from the tank at the same rate. a.) What is the concentration of our solution in the tank initially? (kg/L) concentration = 100/2000 b.) Find the amount of salt in the tank after 5 hours. (kg) amount = e^(-7*5*60/2000)*2000 c.) Find the concentration of salt in the solution in the tank as time approaches infinity. concentration 0.025 (kg/L)
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 16EQ
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![A tank contains 100 kg of salt and 2000 L of water. A solution of a concentration 0.025 kg of salt per liter enters a tank
at the rate 7 L/min. The solution is mixed and drains from the tank at the same rate.
a.) What is the concentration of our solution in the tank initially?
(kg/L)
concentration = 100/2000
b.) Find the amount of salt in the tank after 5 hours
amount = e^(-75*60/2000)*2000
(kg)
c.) Find the concentration of salt in the solution in the tank as time approaches infinity.
concentration = 0.025
(kg/L)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1483efba-5c0a-48b0-afed-42d082147c01%2F08d7367f-a1c7-4cae-a41d-6d043dc1b0d8%2F747969y_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A tank contains 100 kg of salt and 2000 L of water. A solution of a concentration 0.025 kg of salt per liter enters a tank
at the rate 7 L/min. The solution is mixed and drains from the tank at the same rate.
a.) What is the concentration of our solution in the tank initially?
(kg/L)
concentration = 100/2000
b.) Find the amount of salt in the tank after 5 hours
amount = e^(-75*60/2000)*2000
(kg)
c.) Find the concentration of salt in the solution in the tank as time approaches infinity.
concentration = 0.025
(kg/L)
![A tank contains 100 kg of salt and 2000 L of water. A solution of a concentration
0.025 kg of salt per liter enters a tank at the rate 7 L/min. The solution is mixed
and drains from the tank at the same rate. a.) What is the concentration of our
solution in the tank initially? concentration = 100/2000 (kg/L) b.) Find the
amount of salt in the tank after 5 hours. amount = e^(-7*5*60/2000)*2000 (kg)
c.) Find the concentration of salt in the solution in the tank as time approaches
infinity. concentration = 0.025 (kg/L)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1483efba-5c0a-48b0-afed-42d082147c01%2F08d7367f-a1c7-4cae-a41d-6d043dc1b0d8%2Fiqks2g8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A tank contains 100 kg of salt and 2000 L of water. A solution of a concentration
0.025 kg of salt per liter enters a tank at the rate 7 L/min. The solution is mixed
and drains from the tank at the same rate. a.) What is the concentration of our
solution in the tank initially? concentration = 100/2000 (kg/L) b.) Find the
amount of salt in the tank after 5 hours. amount = e^(-7*5*60/2000)*2000 (kg)
c.) Find the concentration of salt in the solution in the tank as time approaches
infinity. concentration = 0.025 (kg/L)
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