A system such as(3/x) + (2/y) = 2(2/x) - (3/y) = 1/4 is not a system of linear equations but can be transformed into a linear system by changing variables. For example, when we substitute u for 1/x and v for 1/y , the system cited becomes3u + 2v = 22u - 3v = 1/4. We can solve this “new” system either by elimination by addition or by substitution (we will leave the details for you) to produce u = 1/2 and v = 1/4 . Therefore, because u = 1/x and v = 1/y , we have 1/x = 1/2 and 1/y = 1/4, Solving these equations yields x = 2 and y = 4. The solution set of the original system is {(2, 4)}. Solve each of the following systems. (3/x) - (2/y) = 13/6 (2/x) + (3/y) = 0
A system such as(3/x) + (2/y) = 2(2/x) - (3/y) = 1/4 is not a system of linear equations but can be transformed into a linear system by changing variables. For example, when we substitute u for 1/x and v for 1/y , the system cited becomes3u + 2v = 22u - 3v = 1/4. We can solve this “new” system either by elimination by addition or by substitution (we will leave the details for you) to produce u = 1/2 and v = 1/4 . Therefore, because u = 1/x and v = 1/y , we have 1/x = 1/2 and 1/y = 1/4, Solving these equations yields x = 2 and y = 4. The solution set of the original system is {(2, 4)}. Solve each of the following systems. (3/x) - (2/y) = 13/6 (2/x) + (3/y) = 0
Chapter4: Systems Of Linear Equations
Section4.3: Solve Mixture Applications With Systems Of Equations
Problem 160E: Take a handful of two types of coins, and write a problem similar to Example 4.25 relating the total...
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A system such as
(3/x) + (2/y) = 2
(2/x) - (3/y) = 1/4 is not a system of linear equations but can be transformed into a linear system by changing variables. For example, when we substitute u for 1/x and v for 1/y , the system cited becomes
3u + 2v = 2
2u - 3v = 1/4. We can solve this “new” system either by elimination by addition or by substitution (we will leave the details for you) to produce u = 1/2 and v = 1/4 . Therefore, because u = 1/x and v = 1/y , we have 1/x = 1/2 and 1/y = 1/4, Solving these equations yields x = 2 and y = 4. The solution set of the original system is {(2, 4)}. Solve each of the following systems. (3/x) - (2/y) = 13/6
(2/x) + (3/y) = 0
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