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College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A system consists of three particles with these masses and velocities: mass 3.00 kg, moving north at 3.00 m/s; mass 4.00 kg, moving
south at 3.80 m/s; and mass 7.00 kg, moving north at 2.00 m/s. What is the total momentum of the system? Take north as the positive
axis. Enter a positive answer if the total momentum is due north and a negative answer if the total momentum is due south.
kg · m/s
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A system consists of three particles with these masses and velocities: mass 3.00 kg, moving north at 3.00 m/s; mass 4.00 kg, moving
south at 3.80 m/s; and mass 7.00 kg, moving north at 2.00 m/s. What is the total momentum of the system? Take north as the positive
axis. Enter a positive answer if the total momentum is due north and a negative answer if the total momentum is due south.
kg · m/s
ok
nt
nt
ences
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- At one particular moment, a 19.0 kg toboggan is moving over a horizontal surface of snow at 4.60 m/s. After 7.50 s have elapsed, the toboggan stops. Use a momentum approach to find the magnitude of the average friction force (in N) acting on the toboggan while it was moving. Narrow_forwardTwo cars collide at an icy intersection and stick together afterward. The first car has a mass of 1400 kg and was approaching at 5.00 m/s due south. The second car has a mass of 850 kg and was approaching at 16.0 m/s due west. a. Calculate the final velocity (magnitude in m/s and direction in degrees counterclockwise from the west) of the cars. (Note that since both cars have an initial velocity, you cannot use the equations for conservation of momentum along the x-axis and y-axis; instead, you must look for other simplifying aspects.) magnitude m/sdirection ° counterclockwise from west b. How much kinetic energy (in J) is lost in the collision? (This energy goes into deformation of the cars.) Jarrow_forwardBlock A of mass m = 1.48 kg moving on a horizontal plane with velocity of vj = 1.71 m/s collides with Block B of the same mass at rest before the collision. After the collision, Block A stops. What is the velocity of Block B Vf after collision? Assume there is no friction between the blocks and the horizontal plane. Keep three significant figures for the answer.arrow_forward
- A system consists of three particles with these masses and velocities: mass 3.00 kg, moving north at 3.00 m/s; mass 4.00 kg, moving south at 4.20 m/s; and mass 7.00 kg, moving north at 2.00 m/s. What is the total momentum of the system? Take north as the positive axis. Enter a positive answer if the total momentum is due north and a negative answer if the total momentum is due south. ____kg ⋅ m/sarrow_forwardAnswer part a, b and carrow_forwardIn a football game, a receiver is standing still, having just caught a pass. Before he can move, a tackler, running at a velocity of +3.77 m/s, grabs him. The tackler holds onto the receiver, and the two move off together with a velocity of +1.82 m/s. The mass of the tackler is 94.1 kg. Assuming that momentum is conserved, find the mass of the receiver. Number i Units Before collision After collisionarrow_forward
- if a stationary 3.2 obect explodes so that: a. one part that is 1.5 kg goes left with 2.6 m/s , what is the mass and velocity of the other part? b. One part that is 1.0 kg goes North at 3.4 m/s and one part that is 1.2 kg goes West at 3.0 m/s, what is the mass and velocity of the third part?arrow_forwardA two dimensional collision between a green and a purple ball, where the purple ball strikes the green. If the data for both objects' velocities (x and y components) versus time are provided, and the mass of the balls are identical, what is a way to determine if the momentum of the system conserved? Explain your methodology. Green ball: vx = 0 m/s from t = 0 s to t = 0.4 s vx = 17.42 m/s from t = 0.5 s to t = 5 s vy = 0 m/s from t = 0 s to t = 0.4 s vy = -8.01 m/s from t = 0.5 s to t = 5 s Purple ball: vx = 22.3 m/s from t = 0 s to t = 0.4 s vx = 4.878 m/s from t = 0.5 s to t = 5 s vy = 2.6 m/s from t = 0 s to t = 0.4 s vy = 10.61 m/s from t = 0.5 s to t = 5 sarrow_forwardA BB gun is fired at a cardboard box of mass m2 = 0.75 kg on a frictionless surface. The BB has a mass of m1 = 0.012 kg and travels at a velocity of v1 = 98 m/s. It is observed that the box is moving at a velocity of v2 = 0.26 m/s after the BB passes through it. PART A) what is the BB's final velocity, vf, in meters per second PART B) if the BB doesnt exit the box, what will the final velocity of the box be in meters per second?arrow_forward
- During a football game, a receiver has just caught a pass and is standing still. Before he can move, a tackler, running at a velocity of +3.9 m/s, grabs and holds onto him so that they move off together with a velocity of +2.3 m/s. If the mass of the tackler is 125 kg, determine the mass of the receiver in kilograms. Assume momentum is conserved. kgarrow_forwardTrain cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, the first having a mass of 180,000 kg and a velocity of 0.300 m/s, and the second having a mass of 125,000 kg and a velocity of −0.120 m/s. (The minus indicates direction of motion.) What is their final velocity (in m/s)? (Enter a number.)m/sarrow_forwardFor a system of three particles moving along a line, an observer in a laboratory measures the following masses and velocities. What is the velocity of the CM of the system? Enter a positive value if the velocity of the CM of the system is in the +x direction and enter a negative value if the velocity of the CM of the system is in the -x direction. Mass (kg) Vx (m/s) 4.00 230 5.0 -120 2.0 +52 m/sarrow_forward
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