A survey of 80 men found that an average amount spent on St. Patrick's day of $48 with a standard deviation of $20. A similar survey of 75 women found they spent an average of $42 with a standard deviation of $16. When testing the hypothesis (at the 5% level of significance) that men spend more than women on St. Patrick's day, what is the critical value? (please round your answer to 2 decimal places)

Q: The annual salaries for people in a particular profession are known to be normally distributed with…

A: Given that the annual salaries for people in a particular profession are known to be normally…

Q: On a recent quiz, the class mean of 74 with the standard deviation of 3.9.  calculate the z-score…

A: Given data  μ = 74σ = 3.9x1 = 95x2 = 70

Q: An article the Journal of the American Medical Association (1992) examined whether the true mean…

A: From the provided information, Sample size (n) = 25 Sample mean (x̅) = 98.25oF Sample standard…

Q: Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest…

A: a. The Z-score of a random variable X is defined as follows: Z = (X – µ)/σ. Here, µ and σ are the…

Q: The average test score in a particular class is m=30. If you scored a 40 and the class (sample)…

A: Introduction: Denote the score of a randomly selected student in a class as X. It is given that the…

Q: aul received a score of 79 on a history test for which the class mean was 70 with a standard…

A:

Q: Ms. Hammell's Algebra 2 students took an exam. the results showed a mean of 78, with a standard…

A: The normal distribution is the most useful theoretical distribution for continuous variables.…

Q: The head of institutional research at a university believed that the mean age of full-time students…

A: The random variable age follows normal distribution. The population mean is 27.4 years. We have to…

Q: In a sample of people, the mean height was  65.2  inches and the heights range from  56  to  70…

A: It is assumed that  denote the height of the person.The random variable X is given as normally…

Q: On a national achievement test score was 850 with a standard deviation of 100. What proportion of…

A:

Q: Use Z scores to compare the given values The tallest living man at one time had a height of 245cm.…

A:

Q: A study was conducted with a sample of 20 college students to see how many students would have low…

A: Suppose a random variable x defines the bone mineral density of students.

Q: a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds?…

A: Here Given  Highest Speed measured=76.6 Mbps Sample Size=50 Sample mean=x¯=18.68 Sample sd= s= 37.17…

Q: b. The test statistic 0° c. The p-value = d. The p-value is ≤ ✓ O α (please show your answer to 3…

A: The given information is:Sample 1:The sample size is The sample mean is The sample standard…

Q: Scores on the verbal reasoning portion of the GRE have a mean of 150 and a standard deviation of 8.…

A: The provided information are: Population mean μ=150 Population standard deviation (σ) = 8 Z-score =…

Q: A standardized test of intelligence is scaled so that the mean IQ is 100, and the standard deviation…

A: Given that information  Mean = mu= 100  Standard deviation = s =15  Zscore = (x - mu)/s

Q: The monthly incomes of 16 students were analyzed and their average was 1000 TL and the standard…

A: Given data,μ=1000σ=200n=16z=2.7x=?

Q: Suppose that another sample of resting heart rates for five Math students was obtained: 72, 68, 66,…

A: From the given data we want to know the data value .

Q: The standard deviation on your last test was 10. The average was a 70. The distribution had a normal…

A: To find out what percentage of the class scored between 60 and 80, we need to utilize the properties…

Q: he scores on a psychology exam were normally distributed with a mean of 65 and a standard deviation…

A: Given,μ=65σ=6

Q: Your instructor wishes to estimate the mean amount of time students spend studying math each…

A: Given that  Margin of error =E =2 Population standard deviation =12.7 95% confidence.

Q: The population mean of happiness is 5.382, with a standard deviation of 1.138. Linda has a z score…

A: We have given that,  Let X be a random variable following normal distribution with mean (Mu) = 5.382…

Q: A test has a mean score of 55 with a standard deviation of 12. Using the Empirical Rule determine…

A:

Q: Assume that adults have IQ scores that are normally distributed with a mean of 95.4 and a standard…

A: Let "X" be the IQ score of adults. Draw the normal curve and shade the area of 0.25 to the left…

Q: (Problem Set #7) In the past, the mean age of consumers of a product was 38 years. Recently the…

A: We have to find out given test statistic...

Q: ou may need to use the appropriate appendix table or technology to answer this question. he average…

A:

Q: The scores on a psychology exam were normally distributed with a mean of 56 and a standard deviation…

A:

Q: To see if young men ages 8-17 years spend a different amount than the national average of $24.44 per…

A: Givensample size(n)=35standard deviation(s)=3.70Mean(x)=23.37α=0.05

Q: Test scores for the SAT are close to normal with an average of 850 and a standard deviation of 100.…

A: Given information: Mean SAT test scores μ=850 Standard deviation of SAT test scores σ=100 The SAT…

Q: You are provided with a mean of 28.18 with a standard deviation of 4.33.  What percent of students…

A:

Q: 3. A taxi company claims that its drivers have an average of at least 12.4 years' experience. In a…

A: Givensample size(n)=15Mean(x)=11.2standard deviation(s)=2α=0.10

Q: you created a survey that measue Depression In you want to test people. the Claim that the mean.…

A: Solution-: Given: x¯=6.7,μ0=6.5,n=145,s=1.5 We test the claim that the mean measurement of…

Q: Suppose the exam average in a class is 55% with a standard deviation of 4. What proportion of…

A: The random variable score follows normal distribution. The population mean is 55.         The…

Q: For a certain type of job, it costs a copany an average of $231 to train an employee to perform the…

A: From the provided information, Mean (µ) = 231 Standard deviation (σ) = 5