
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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A student was asked to find a 90% confidence interval for widget width using data from a random
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- A student was asked to find a 98% confidence interval for the proportion of students who take notes using data from a random sample of size n = 86. Which of the following is a correct interpretation of the interval 0.11 < p < 0.33? Check all that are correct. The proportion of all students who take notes is between 0.11 and 0.33, 98% of the time. With 98% confidence, a randomly selected student takes notes in a proportion of their classes that is between 0.11 and 0.33. There is a 98% chance that the proportion of the population is between 0.11 and 0.33. There is a 98% chance that the proportion of notetakers in a sample of 86 students will be between 0.11 and 0.33. With 98% confidence, the proportion of all students who take notes is between 0.11 and 0.33.arrow_forwardA researcher is interested in studying the use of hypnosis to relieve pain. She took a random sample of 16 subjects and measured their sensory ratings. The mean of the sensory ratings was found to be 7.5 and standard deviation to be 2.3. It is known that the sensory ratings are normally distributed. Construct a 99% confidence interval for the mean sensory ratings of the population. a) (5.81, 9.19) b) (6.27, 8.73) c) (6.36, 8.64) d) (6.02, 8.98)arrow_forwardA simple random sample of size n=40 is drawn from a population. The sample mean is found to be x=121.3 and the sample standard deviation is found to be x=12.3. Construct a 99% confidence interval for the population mean.arrow_forward
- A student was asked to find a 95% confidence interval for widget width using data from a random sample of size n = 23. Which of the following is a correct interpretation of the interval 12.3 < μ < 25? Check all that are correct. There is a 95% chance that the mean of a sample of 23 widgets will be between 12.3 and 25. There is a 95% chance that the mean of the population is between 12.3 and 25. The mean width of all widgets is between 12.3 and 25, 95% of the time. We know this is true because the mean of our sample is between 12.3 and 25. With 95% confidence, the mean width of a randomly selected widget will be between 12.3 and 25. With 95% confidence, the mean width of all widgets is between 12.3 and 25.arrow_forwardA student was asked to find a 90% confidence interval for widget width using data from a random sample of size n = 20. Which of the following is a correct interpretation of the interval (11.5,21.6)? There is a 90% chance that the mean of a sample of 20 widgets will be between 11.5 and 21.6. The mean width of all widgets is between 11.5 and 21.6, 90% of the time. We know this is true because the mean of our sample is between 11.5 and 21.6. With 90% confidence, the mean width of a randomly selected widget will be between 11.5 and 21.6. We are 90% confident the mean width of all widgets is between 11.5 and 21.6. There is a 90% chance that the mean of the population is between 11.5 and 21.6.arrow_forwardA student was asked to find a 98% confidence interval for widget width using data from a random sample of size n = 26. Which of the following is a correct interpretation of the interval 13.5 < μ < 29.3? Check all that are correct. The mean width of all widgets is between 13.5 and 29.3, 98% of the time. We know this is true because the mean of our sample is between 13.5 and 29.3. With 98% confidence, the mean width of a randomly selected widget will be between 13.5 and 29.3. There is a 98% chance that the mean of a sample of 26 widgets will be between 13.5 and 29.3. There is a 98% chance that the mean of the population is between 13.5 and 29.3. With 98% confidence, the mean width of all widgets is between 13.5 and 29.3.arrow_forward
- You measure 49 randomly selected textbooks' weights, and find they have a mean weight of 31 ounces. Assume the population standard deviation is 13.7 ounces. Based on this, construct a 95% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places <μ<arrow_forwardA sample of 20 cows is drawn to estimate the mean weight of a large herd of cattle. If the standard deviation of the sample is 96 kg, what is the margin of error in a 90% confidence interval estimate?arrow_forwardSuppose a randomly selected sample of n = 69 men has a mean foot length of x = 27.9 cm, and the standard deviation of the sample is 3 cm. Calculate an approximate 95% confidence interval for the mean foot length of men. (Round the answers to one decimal place.)arrow_forward
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