A student needs to prepare a ¹H NMR sample for an organic compound soluble in chloroform (CHCI3). The student cannot use CHCl3 as the solvent for the sample, but rather uses deuterated chloroform (CDC13) because: O CDCl3 is more polar. O CDC13 will not produce a signal in the ¹H NMR spectrum, and therefore will not mask the signals of the compound. O The compound will be more soluble in CDCI 3. O CDCl3 is cheaper than CHCI 3.

Organic Chemistry
9th Edition
ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter13: Structure Determination: Nuclear Magnetic Resonance Spectroscopy
Section13.1: Nuclear Magnetic Resonance Spectroscopy
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A student needs to prepare a ¹H NMR sample for an organic compound soluble in chloroform (CHCI3). The student cannot use CHCI 3
as the solvent for the sample, but rather uses deuterated chloroform (CDC13) because:
O CDC13 is more polar.
O CDC13 will not produce a signal in the ¹H NMR spectrum, and therefore will not mask the signals of the compound.
O The compound will be more soluble in CDCI 3.
O CDC13 is cheaper than CHCI 3.
Transcribed Image Text:A student needs to prepare a ¹H NMR sample for an organic compound soluble in chloroform (CHCI3). The student cannot use CHCI 3 as the solvent for the sample, but rather uses deuterated chloroform (CDC13) because: O CDC13 is more polar. O CDC13 will not produce a signal in the ¹H NMR spectrum, and therefore will not mask the signals of the compound. O The compound will be more soluble in CDCI 3. O CDC13 is cheaper than CHCI 3.
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