A student determines the value of the equilibrium constant to be 8.18x10-37 for the following reaction. H₂S(g) + 2H₂O(l)—3H₂(g) + SO₂(g) Based on this value of Keq: AG° for this reaction is expected to be (greater, less) zero. than Calculate the free energy change for the reaction of 1.68 moles of H₂S(g) at standard conditions at 298K. AG rxn= kJ

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A student determines the value of the equilibrium constant to be
8.18x10-37 for the following reaction.
H₂S(g) + 2H₂O(l)—3H₂(g) + SO₂(g)
Based on this value of Keq:
AG° for this reaction is expected to be (greater, less)
zero.
than
Calculate the free energy change for the reaction of 1.68 moles of
H₂S(g) at standard conditions at 298K.
AG rxn=
kJ
Transcribed Image Text:A student determines the value of the equilibrium constant to be 8.18x10-37 for the following reaction. H₂S(g) + 2H₂O(l)—3H₂(g) + SO₂(g) Based on this value of Keq: AG° for this reaction is expected to be (greater, less) zero. than Calculate the free energy change for the reaction of 1.68 moles of H₂S(g) at standard conditions at 298K. AG rxn= kJ
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