A student determines the value of the equilibrium constant to be 7.69x10-37 for the following reaction. H2S(g) + 2H20(1)3H2(g) + so2(g) Based on this value of Keg AG° for this reaction is expected to be (greater, less) than zero. Calculate the free energy change for the reaction of 1.72 moles of H2S(g) at standard conditions at 298K. AG°rxn kJ

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A student determines the value of the equilibrium constant to be
7.69x10-37 for the following reaction.
H2S(g) + 2H20(1)-3H2(g) + SO2(g)
Based on this value of Keg
AG° for this reaction is expected to be (greater, less)
than
zero.
Calculate the free energy change for the reaction of 1.72 moles of
H2S(g) at standard conditions at 298K.
AG°rxn =
kJ
Transcribed Image Text:A student determines the value of the equilibrium constant to be 7.69x10-37 for the following reaction. H2S(g) + 2H20(1)-3H2(g) + SO2(g) Based on this value of Keg AG° for this reaction is expected to be (greater, less) than zero. Calculate the free energy change for the reaction of 1.72 moles of H2S(g) at standard conditions at 298K. AG°rxn = kJ
Consider the reaction
4HCI(g) + 02(g)2H20(g) + 2C12(g)
Using the standard thermodynamic data in the tables linked above,
calculate AG for this reaction at 298.15K if the pressure of each
gas is 12.69 mm Hg.
ANSWER:
kJ/mol
Transcribed Image Text:Consider the reaction 4HCI(g) + 02(g)2H20(g) + 2C12(g) Using the standard thermodynamic data in the tables linked above, calculate AG for this reaction at 298.15K if the pressure of each gas is 12.69 mm Hg. ANSWER: kJ/mol
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