A student begins at rest and then walks north at a speed of v1=0.65m/s. The student then turns south and walks at a speed of v2=0.28m/s. Take north to be the positive direction. a)What is the student's overall average velocity vavg, in meters per second, for the full trip assuming the student spent equal times at speeds v1 and v2?
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
A student begins at rest and then walks north at a speed of v1=0.65m/s. The student then turns south and walks at a speed of v2=0.28m/s. Take north to be the positive direction.
a)What is the student's overall average velocity vavg, in meters per second, for the full trip assuming the student spent equal times at speeds v1 and v2?
b) If the student travels in the stated directions for 30.0s30.0s at speed v1 and 20.0s at speed v2, what is the net displacement, in meters, during the trip?
c) If it takes the student 1.2s to reach the speed v1, from rest, what is the magnitude, in meters per squared second, of the student’s average acceleration during that time?
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 3 images