A string oscillates according to the equation y' = (0.367 cm) sin[(n/5.0 cm¯²)x] cos[(45.2 n s)t]. What are the (a) amplitude and (b) speed of the two waves (identical except for direction of travel) whose superposition gives this oscillation? (c) What is the distance between nodes? (d) What is the transverse speed of a particle of the string at the position x = 2.20 cm when t = 1.06 s?

A wave is represented by the equation y = (5.00 mm)sin [(5.00 mm¯¹) x − (8.00 s¯¹) t] + (2.00 mm) cos [(5.001 and t is in seconds. What is the amplitude of the wave? i mm n¯¹) x − (8.00 s¯¹) t], where y is in millimeters mm

A displacement function y is produced when there are two waves present with displacements y 1 = 6.00 sin (4.00 t - 6.00 x ) and y 2 = 6.00 sin (4.00 t - 6.00 x ). What is the amplitude of the new wave function? (Unitless quantity.)

Transverse waves on a string have a wave speed of 8.00 m / s, an amplitude of 0.070 m and a wavelength of 0.320 m.These waves travel in the +x direction, and at t = 0 the end x = 0 of the chord is at y = 0 and is moving downward. (a) Find the frequency, period and wave number k= 2/λ of these waves. (b) Write the equation for y (x, t) describing these waves. (c) Find the transverse displacement of a point on the chord at x = 0: 360m at time t = 0: 150s. (Show the formulas with explanations and steps please)