A straight conductor of length I moves with an acceleration a = 0.1 ms² at right angles to a magnetic field of uniform strength B = 10 T. The e.m.f. between the ends of the conductor increased from 0 to 5 V during the first 20 s after the beginning of motion. Calculate l and give your answer in SI units.

A metal rod (mass m = 0.10 kg, resistance R = 2.0 2) is lying on top of two conducting rails that are separated by 1.6 m. The rails are located in a uniform magnetic field B = 0.15 T, which is perpendicular to the plane of the rails, as shown below. a. Determine the force (magnitude and direction) acting on the metal bar at the moment when a 12.0 V battery is connected to the rails. Assume that the resistance of the rails and connecting wires is negligible. Ignore the friction between the rod and the rails. b. The metal rod moves with an acceleration until it reaches a constant terminal speed v. Explain why. Determine the terminal speed v. Conducting rails 90* 1.6m

A potential difference of 0.0895 V is developed across a 9.46 cm long wire as it moves through a magnetic field at 5.39 m/s. The magnetic field is perpendicular to the axis of the wire. What is the strength (in T) of the magnetic field? What is the direction of the magnetic field?

A proton moves perpendicular to a uniform magnetic field B at a speed of 1.10 x 10' m/s and experiences an acceleration of 1.60 x 1013 m/s2 in the positive x direction when its velocity is in the positive z direction. Determine the magnitude and direction of the field. 0.7952e-2 magnitude Your response differs from the correct answer by more than 10%. Double check your calculations. T

True or False A moving charge entering a magnetic field parallel to the field will move in a straight line. A man whose resistance is 10,000 Ω has 120 volt potential difference across his body.  This would cause a fatal shock. Adding resistors to a parallel circuit decreases the equivalent resistance. The resistance of a resistor increases with decreased temperature The terminal voltage (V) of a battery is always less than its EMF (ξ). The electric field E is a scalar but the electric potential V is a vector.

A metal strip 9.11 cm long, 0.864 cm wide, and 0.660 mm thick moves with constant velocity through a uniform magnetic field B = 1.77 mT directed perpendicular to the strip, as shown in the figure. A potential difference of 4.29 μV is measured between points x and y across the strip. Calculate the speed v. Number i Units X X

Consider a straight conductor of length 6.3 cm. The conductor moves at right angles to a magnetic field of uniform strength B = 10-3 T generating e.m.f. of 2.5 × 10-5 v. Calculate the velocity of the straight conductor. Give your answer in SI units. Answer: Choose... + Next page Previous page

A +1.00 µC charged brass marble has a velocity of 15.0 m/s in the positive direction, or ū = (15.0 m/s, 0.00 m/s, 0.00 m/s), and moves in the presence of a 2.00 T magnetic field in the positive z direction, or B = (0.00 T, 0.00 T, 2.00 T). a. What is the vector valued magnetic force on the +1.00 µC brass marble? You may state a magnitude and direction or give the force as an ordered triple. b. Suppose that instead of having a charge of +1.00 µC, the charge is of the same magnitude but negative, or -1.00 µC. What is the vector valued magnetic force assuming the same magnetic field as in part (a)? c. Now, suppose a +2.00 µC charged osmium marble moves with a velocity of 15.0 m/s in the negative z direction, or parallel to the magnetic field in parts (a) and (b). What is the magnetic force on the marble?

A velocity selector in a mass spectrometer uses a 0.130 T magnetic field.  a. What electric field strength (in volts per meter) is needed to select a speed of 3.70 ✕ 106 m/s?  b. What is the voltage (in kilovolts) between the plates if they are separated by 1.00 cm?

Pr1. The figure shows the cross-section of a long, straight, cylindrical coil (solenoid) of radius r = 10 cm. The number of turns per unit length is n = 500 m-1. A direct current I = 1,0 A flows clockwise in the solenoid. A charged particle accelerated by a voltage 1000 V enters into the solenoid through a gap between the coils at point A. The velocity of the particle at point A is pointing along the radius. The particle is traveling inside the solenoid in a plane perpendicular to its axis and exits at point C at an angle a = 60° to its initial direction. 60 Av a) Determine the sign of the charge of the particle. b) What is the radius of the particle's trajectory? c) Find the charge-to-mass (Q/m) ratio of the particle. (The magnetic permeability of vacuum is µo = 47 - 10-7 Vs/Am.)