A stone was dropped off a cliff and hit the ground with a speed of 152 ft/s. What is the height of the cliff? Part 1 of 4 We know that s(t) = at² + vot+Sg. In this situation, we have a = -32.17 X Part 2 of 4 We have s(t) = at² + vot + 5o = -16t² + h. Therefore, the velocity is v(t) = s'(t) = -32, Vo 358.35 X 0 F and so = h, where h is the height of the cliff that we wish to find.

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Chapter5: Relativity
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A stone was dropped off a cliff and hit the ground with a speed 152 ft/s. What is the height of the cliff?
Part 1 of 4
We know that s(t) = 1at² + vot + so. In this situation, we have a = -32.17 X
Part 2 of 4
We have s(t) = at² + vot + so = -16t² +h. Therefore, the velocity is
v(t) = s'(t) =
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-32
vo
358.35 X
and so h, where h is the height of the cliff that we wish to find.
Transcribed Image Text:Tutorial Exercise A stone was dropped off a cliff and hit the ground with a speed 152 ft/s. What is the height of the cliff? Part 1 of 4 We know that s(t) = 1at² + vot + so. In this situation, we have a = -32.17 X Part 2 of 4 We have s(t) = at² + vot + so = -16t² +h. Therefore, the velocity is v(t) = s'(t) = Submit Skip (you cannot come back) -32 vo 358.35 X and so h, where h is the height of the cliff that we wish to find.
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