A stone is launched vertically upward from a cliff 384 ft above the ground at a speed of 32 ft/s. Its height above the ground t seconds after the launch is given by s= - 16t + 32t +384 for 0sts6. When does the stone reach its maximum height? Find the derivative of s.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
A stone is launched vertically upward from a cliff 384 ft above the ground at a speed of 32 ft/s. Its height above the ground t seconds after the launch is given by
S= - 161 + 32t + 384 for 0 sts6. When does the stone reach its maximum height?
Find the derivative of s.
s' =
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Transcribed Image Text:A stone is launched vertically upward from a cliff 384 ft above the ground at a speed of 32 ft/s. Its height above the ground t seconds after the launch is given by S= - 161 + 32t + 384 for 0 sts6. When does the stone reach its maximum height? Find the derivative of s. s' = Enter your answer in the answer box and then click Check Answer. 1 part remaining Clear All Check Answer 14 Example 2 Solution MacBook Air DII F2 F4 F5 F6 F7 FB F9 F10 FII F3 23 2$ % & * 3 4. 6. 7 8. %3D Q W E Y P K L. ーの エ ート A\
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