A stepped bar is held in equilibrium by several forces acting at different points along the length, as shown in the figure below. The magnitudes for three of the forces are F₂ = 31 kN, F3 = 23 kN, and F₁ = 17 kN. All forces act parallel to the axis of the bar, and both pairs of forces F₂ and F3 are located the same distance from the centerline of the bar. Determine the internal normal forces (P) at points A, B, and C. Note: Express tension forces as positive (+) and compression forces as negative (-). F₁ F₂ A F₂ PA number (rtol-0.01, atol=1e-05) PB number (rtol-0.01, atol=1e-05) Pc = number (rtol=0.01, atol=1e-05) B kN ? kN > kN 7 F₁ F3 E.C. LL

International Edition---engineering Mechanics: Statics, 4th Edition
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Author:Andrew Pytel And Jaan Kiusalaas
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Chapter6: Beams And Cables
Section: Chapter Questions
Problem 6.6P: Find the internal force systems acting on sections 1 and 2.
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A stepped bar is held in equilibrium by several forces acting at different points along the length, as shown in
the figure below. The magnitudes for three of the forces are F₂ = 31 kN, F3 = 23 kN, and F₁ = 17 kN. All
forces act parallel to the axis of the bar, and both pairs of forces F₂ and F3 are located the same distance from
the centerline of the bar. Determine the internal normal forces (P) at points A, B, and C.
Note: Express tension forces as positive (+) and compression forces as negative (-).
F₁
PA =
PB =
Pc
F₂
A:
F₂
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
B
kN
kN >
kN €
F₂
C.
F₁
Transcribed Image Text:A stepped bar is held in equilibrium by several forces acting at different points along the length, as shown in the figure below. The magnitudes for three of the forces are F₂ = 31 kN, F3 = 23 kN, and F₁ = 17 kN. All forces act parallel to the axis of the bar, and both pairs of forces F₂ and F3 are located the same distance from the centerline of the bar. Determine the internal normal forces (P) at points A, B, and C. Note: Express tension forces as positive (+) and compression forces as negative (-). F₁ PA = PB = Pc F₂ A: F₂ number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) B kN kN > kN € F₂ C. F₁
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