(a) State the null hypothesis H and the alternative hypothesis H₁. Ho :O H₁:0 (b) Determine the type of test statistic to use. Chi-Square Degrees of freedom: (c) Find the value of the test statistic. (Round to three or more decimal places.) (d) Find the p-value (Bound to ro decimal places

Consider the data. xi 1 2 3 4 5 yi 3 7 5 11 14     (D) Use the t test to test the following hypotheses (? = 0.05): H0: β1  =  0 Ha: β1 ≠ 0   Find the value of the test statistic. (Round your answer to three decimal places.) =____   Find the p-value. (Round your answer to four decimal places.) p-value = _____   State your conclusion. (A) Reject H0. We cannot conclude that the relationship between x and y is significant.(B) Do not reject H0. We cannot conclude that the relationship between x and y is significant.      (C) Do not reject H0. We conclude that the relationship between x and y is significant. (D) Reject H0. We conclude that the relationship between x and y is significant.     (E) Use the F test to test the hypotheses in part (d) at a 0.05 level of significance. Present the results in the analysis of variance table format. Set up the ANOVA table. (Round your values for MSE and F to two decimal places, and your p-value to three decimal…

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Question list O O Question 21 O Question 22 O Question 23 Question 24 Question 25 Question 26 uestion 27 estion 28 stion 29 ↓ K The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a = 0.01, (b) a = 0.05, and (c) a=0.10. P=0.0138 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? OA. Fail to reject Ho because the P-value, 0.0138, is less than α=0.01. OB. Fail to reject Ho because the P-value, 0.0138, is greater than a = 0.01. OC. Reject Ho because the P-value, 0.0138, is less than a = 0.01. OD. Reject Ho because the P-value, 0.0138, is greater than a = 0.01. (b) Do you reject or fail to reject Ho at the 0.05 level of significance? O A. Reject Ho because the P-value, 0.0138, is less than a = 0.05. OB. Reject Ho because the P-value, 0.0138, is greater than a = 0.05. OC. Fail to reject Ho because the P-value, 0.0138, is less than a = 0.05. O D. Fail to reject Ho because the P-value, 0.0138,…

Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test. Ho: p = 0.8 versus H₁: p > 0.8 n = 125; x = 105; α = 0.1 Click here to view page 1 of the table. Click here to view page 2 of the table. Calculate the test statistic, Zo. Zo (Round to two decimal places as needed.) Identify the P-value. = P-value = (Round to three decimal places as needed.) Choose the correct result of the hypothesis test for the P-value approach below. A. Do not reject the null hypothesis, because the P-value is less than a. B. Do not reject the null hypothesis, because the P-value is greater than α. C. Reject the null hypothesis, because the P-value is greater than a. O D. Reject the null hypothesis, because the P-value is less than α.

Help with finding: test statistic p Value  reject null hypothesis

Determine the test statistic for this hypothesis test. (Round to two decimal places as needed.)

Test the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test.   H0​: p=0.9  versus  H1​: p>0.9 n=200​; x=190​; α= 0.05   Calculate the test​ statistic, z0.

Scenario: I'm interested in whether there is a relationship between Team (A vs. B) and Outcome (Good vs. Bad). Below are the data.  Test the null hypothesis that the categories are independent.  α= .05.   Team A Team B Good Outcome fo = 75 fe = fo = 45 fe = Bad Outcome fo = 25 fe = fo = 5 fe =   degrees of freedom, df = ______, and the Chi Square critical boundary = ______

How is the hatching of water python eggs influenced by the temperature of the snake's nest? Researchers randomly assigned newly laid eggs to one of three water temperatures: hot, neutral, or cold. Hot duplicates the extra warmth provided by the mother python, and cold duplicates the absence of the mother. The table shows the result of the experiment. The researchers will use a chi-square test for homogeneity to analyze the findings. Hatching status Yes No Total Cold 16 11 27 Water Temperature Neutral Hot 38 75 18 56 104 Total 129 58 187 Which of the following is false? All of the conditions are met for conducting a chi- square test for homogeneity. The data came from 3 groups in a randomized experiment. All expected counts are at least 5. The 10% condition is met. The 10% condition is not needed because the eggs were not randomly selected from the population. Incorrect