A star has a mass of 2.42 x 1030 kg and is moving in a circular orbit about the center of its galaxy. The radius of the orbit is 1.5 x 104 light-years (1 light-year = 9.5 x 1015 m), and the angular speed of the star is 1.8 x 10-15 rad/s. (a) Determine the tangential speed of the star. (b) What is the magnitude of the net force that acts on the star to keep it moving around the center of the galaxy?

Your answer is partially correct. Review Conceptual Example 2 before attempting this problem. The moon has a diameter of 3.48 x 106 m and is a distance of 3.85 x 108 m from the earth. The sun has a diameter of 1.39 x 10⁹ m and is 1.50 x 10¹1 m from the earth. Determine (in radians) the angles subtended by (a) the moon and (b) the sun, as measured by a person standing on the earth. (c) Determine the ratio of the apparent circular area of the moon to the apparent circular area of the sun. These calculations determine whether a total eclipse of the sun is really "total." (a) Number 0.00904 (b) Number i 0.0093 (c) Number i 0.945 Units rad Units Units rad No units

A star has a mass of 1.23 x 1030 kg and is moving in a circular orbit about the center of its galaxy. The radius of the orbit is 1.0 x 104light-years (1 light-year = 9.5 x 1015 m), and the angular speed of the star is 1.7 x 10-15 rad/s. (a) Determine the tangential speed of the star. (b) What is the magnitude of the net force that acts on the star to keep it moving around the center of the galaxy?

1. The horizontal circular platform weighs 500 lb and has a radius of gyration of kz = 8 ft from the z-axis passing through O. The platform is free to rotate about the z-axis and is initially at rest. A person having a weight of 150 lb begins to run along the edge in a circular path of radius 10 ft. If they maintain a speed of 4 ft/s relative to the platform, determine the angular velocity of the 10 ft platform. Neglect friction. I don't think we have dealt with relative velocity in this context, but it follows our earlier relative velocity treatment. Here all speeds are in the t-direction. vp is the speed of the person, and vp is the speed of the disk at the location of the person. Then vp = vp + Vp/D, same as before. You are given vpp = 4 ft/s.

A planet orbits a star, in a year of length 2.29 x 10’ s, in a nearly circular orbit of radius 3.81 x 1011 m. With respect to the star, determine (a) the angular speed of the planet, (b) the tangential speed of the planet, and (c) the magnitude of the planet's centripetal acceleration. (a) Number i Units (b) Number i Units (c) Number i Units >